Question

Find two numbers, if their sum is 49 and their difference is 1/2 .

Answer 1

Answer:

$x=24\frac{3}{4}\\ y=24\frac{1}{4}$

Step-by-step explanation:

Let the two numbers be x and y

So we have:

$x +y = 49\\x-y=\frac{1}{2}$

using the elimination method, add the two equations together:

$2x=49\frac{1}{2} \\2x=\frac{99}{2}$

solve for x:

$x=\frac{99}{4}\\x=24\frac{3}{4}$

substitute our value for x back into the first equation we made:

$x+y=49\\(\frac{99}{4}) + y=49\\y=49-\frac{99}{4}\\y=\frac{97}{4} \\ y=24\frac{1}{4}$

therefore,

$x=24\frac{3}{4}\\ y=24\frac{1}{4}$