6a. 1 - 2sin(x)² - 2cos(x)² = 1 - 2(sin(x)² +cos(x)²) = 1 - 2·1 = -1
6c. tan(x) + sin(x)/cos(x) = tan(x) + tan(x) = 2tan(x)
6e. 3sin(x) + tan(x)cos(x) = 3sin(x) + (sin(x)/cos(x))cos(x) = 3sin(x) +sin(x) = 4sin(x)
6g. 1 - cos(x)²tan(x)² = 1 - cos(x)²·(sin(x)²)/cos(x)²) = 1 -sin(x)² = cos(x)²
Answer:
135%
Step-by-step explanation:
To represent a decimal to percentage, multiply by 100
1.35 x 100 = 135
If my answer is incorrect, pls correct me!
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-Chetan K
Answer:
The answer is 6/5
Step-by-step explanation:
Answer:
12
Step-by-step explanation:
Pythagorean theorem
a²+b²=c²
a²+35²=37²
a²+1225=1369
manipulate the equation
1225-1369=-a²
-144=-a²
√-144=12
a=12
Answer:
Step-by-step explanation:
You have no grounds for making a statement like that. There are a variety of reasons why you might not get immediate answers. Be patient.
I will do the second part of this question (finding the first three numbers):
a(4) = a(3)*(-3) + 2 = -148, so a(3)*(-3) = -150 and a(3) = -50
a(3) = 50
a(2) = a(3)*(-3) + 2 = 50, so -3*a(3) = 48 and a(d) = -16
a(1) = a(2)*(-3) + 2 = -16, so a(2)*(-3) = -18 and a(1) = 6
The procedure for finding a(5), a(6) and a(7) is exactly the same.
