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Veseljchak [2.6K]
3 years ago
13

Imagine tying a string to a ball and twirling it around you. How is this similar to the moon orbiting the Earth? In this example

, what is providing the constantly changing, inward force?
Physics
2 answers:
Tema [17]3 years ago
4 0
Its similar to the moon orbiting the earth because lets say that the sing is moon and the ball is earth has the "moon" orbits around the "earth" the string ends up tying around the ball till its no more


i think i hope this example helps you somehow srry that i dont know more then that :/
Archy [21]3 years ago
4 0

Answer:

It is a similar case, given that both can be modeled as uniform circular motion. The inward force for the Earth-moon case is provided by gravity's force, and in the case of the ball-string it is provided by the tension on the string.

Explanation:

There are parellels between both cases:

in the Earth-moon movement, the mass of each astral body generates a pulling force (gravity) which, given the correct circumstances, makes each object revolve a common center of mass, almost in a circular trajectory. Of course, since we are not in such point in space but standing on Earth, we see as the moon is revolving around the earth. The inward force would be gravity in this case. There are other forces involved such as the pulling on the sun, but it is common to both bodies so it is not relevant in this picture.

The ball swirling around you is possible because it is attached to a rope or string, which constantly pulls the ball towards the center (you). The force involved here is called the 'tension' on the rope. The circular movement is a combination of tangential velocity and inward radial force. There are other forces which are more relevant here, such as the friction with the air and the acceleration of gravity of the Earth on the ball, which can actually alter the trajectory of the ball. The pulling must supply some pushing force to counter those forces.

For more information and insight on this problem I recommend videos on uniform circular motion and centripetal forces.

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Answer:

13.1

Explanation:

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nirvana33 [79]

Answer:

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  2. Wave interference can be thought of as the opposite of destructive ---> constructive anda hencd meet and interact on the same medium such that answer B is correct
6 0
2 years ago
An electric heater is rated 1000watts. If a current of 5A pass through the heater, find the value of its resistance.​
ICE Princess25 [194]

Answer: R=40 Ω

Explanation: P=I^{2} R

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5 0
3 years ago
2 pts
const2013 [10]

Answer:

I think the answer 1

Explanation:

im probably wrong too i dont know

5 0
2 years ago
PRACTICE ANOTHER A cube of wood having an edge dimension of 19.7 cm and a density of 647 kg/m3 floats on water. (a) What is the
dedylja [7]

CHECK COMPLETE QUESTION

The cube of wood having an edge dimension of 19.7cm and a density of 647kg/m3 floats on water

(a) What is the distance from the horizontal top surface of the cube to the water level answer in cm

(b) What mass of lead should be placed on the cube so that the top of the cube will be just level with the water surface answer in kg

Answer:

a)6.29cm

b)2.78 kg

Explanation:

Given:

Let us calculate the volume first, we were given dimension as 19.7cm=0.197m

Volume is (0.197 meters)³ = 0.00764m³

Then we can calculate the mass as;

Given mass is 647 kg/m³ x 0.00774m³ = 4.947kg

The weight = mass × acceleration due to gravity

weight = 4.947 x 9.8 N/kg = 48.44N

By Floating we can say the the buoyancy force has to equal the weight (48.44 N) which has

which is equal to the weight of volume of the displaced water. Or the mass, the calculation is the same.

We know that density of fresh water at 20ºC is 998 kg/m³

Then we can calculate the volume of displaced water as

4.947 kg / 998 kg/m³ = 0.00496 m³

We know that the displaced water has a shape of a rectangular solid with 0.197 meters on the two horizontal dimensions, and h as the height to the surface then

V = 0.197²h = 0.00496

0.00496= 0.197²h

h = 0.1278 meters or 12.78 cm

Then the the distance exposed, would be 19.7–12.78 = 6.29 cm

b) ifthe cube is fully submerged, the volume of the displaced water is 0.00774m³

mass of displaced water is 0.00774m³ x 998 kg/m³ = 7.724 kg

Added mass is the mass of the displaced water – mass of block

= 7.724–4.947 = 2.78 kg

5 0
3 years ago
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