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Veseljchak [2.6K]
3 years ago
13

Imagine tying a string to a ball and twirling it around you. How is this similar to the moon orbiting the Earth? In this example

, what is providing the constantly changing, inward force?
Physics
2 answers:
Tema [17]3 years ago
4 0
Its similar to the moon orbiting the earth because lets say that the sing is moon and the ball is earth has the "moon" orbits around the "earth" the string ends up tying around the ball till its no more


i think i hope this example helps you somehow srry that i dont know more then that :/
Archy [21]3 years ago
4 0

Answer:

It is a similar case, given that both can be modeled as uniform circular motion. The inward force for the Earth-moon case is provided by gravity's force, and in the case of the ball-string it is provided by the tension on the string.

Explanation:

There are parellels between both cases:

in the Earth-moon movement, the mass of each astral body generates a pulling force (gravity) which, given the correct circumstances, makes each object revolve a common center of mass, almost in a circular trajectory. Of course, since we are not in such point in space but standing on Earth, we see as the moon is revolving around the earth. The inward force would be gravity in this case. There are other forces involved such as the pulling on the sun, but it is common to both bodies so it is not relevant in this picture.

The ball swirling around you is possible because it is attached to a rope or string, which constantly pulls the ball towards the center (you). The force involved here is called the 'tension' on the rope. The circular movement is a combination of tangential velocity and inward radial force. There are other forces which are more relevant here, such as the friction with the air and the acceleration of gravity of the Earth on the ball, which can actually alter the trajectory of the ball. The pulling must supply some pushing force to counter those forces.

For more information and insight on this problem I recommend videos on uniform circular motion and centripetal forces.

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Could I get help on this question please . My parents won’t help me /:
vovikov84 [41]

Answer:

Tarzan will be moving at 7.4 m/s.

Explanation:

From the question given above, the following data were obtained:

Height (h) of cliff = 2.8 m

Initial velocity (u) = 0 m/s

Final velocity (v) =?

NOTE: Acceleration due to gravity (g) = 9.8 m/s²

Finally, we shall determine how fast (i.e final velocity) Tarzan will be moving at the bottom. This can be obtained as follow:

v² = u² + 2gh

v² = 0² + (2 × 9.8 × 2.8)

v² = 0 + 54.88

v² = 54.88

Take the square root of both side

v = √54.88

v = 7.4 m/s

Therefore, Tarzan will be moving at 7.4 m/s at the bottom.

3 0
3 years ago
State guy lussac law
tatuchka [14]

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7 0
3 years ago
. Một con lắc đơn có chiều dài dây treo 1m dao động điều hoà treo trong một xe chạy trên mặt phẳng nghiêng
lyudmila [28]

Answer:

C

Explanation:

hope for help ....im expert

6 0
3 years ago
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What is the soil fabric?
inessss [21]

Answer:

The term soil fabric refers to the geometrical arrangement of individual particles in a soil, including the geometrical distribution of pore spaces. Soil fabric may be used to describe the particle arrangement in both cohesive soils such as clays and granular soils such as silts, sands, and gravels.

5 0
2 years ago
Choose the statement(s) that is/are true about the ratio \frac{C_p}{C_v} C p C v for a gas? (Ii) This ratio is the same for all
Blababa [14]

Answer:

(i) false

(ii) true

(iii) true

(iv) false

Explanation:

(i) The ratio of Cp and Cv is not constant for all the gases. It is because the value of cp and Cv is different for monoatomic, diatomic and polyatomic gases.

So, this is false.

(ii) For monoatomic gas

Cp = 5R/2, Cv = 3R/2

So, thier ratio

Cp / Cv = 5 / 3 = 1.67

This statement is true.

(iii) for diatomic gases

Cp = 7R/2, Cv = 5R/2

Cp / Cv = 7 / 5 = 1.4

This statement is true.

(iv) It is false.

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