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Alex
3 years ago
10

If the electric field is 100N/C at a distance of 50 cm from a point charge , what is the value of ?.

Physics
1 answer:
White raven [17]3 years ago
5 0

Answer:

e \:  =  \:  \frac{kq}{{r}^{2} }

then q = e r² / k

then q = 100 * (50 ×10^-2)² / 9×10^9 = 2.777777778×10^-9 C

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