If the electric field is 100N/C at a distance of 50 cm from a point charge , what is the value of ?.

Physics

1 answer:

White raven [17]3 years ago

5 0

Answer:

$e \: = \: \frac{kq}{{r}^{2} }$

then q = e r² / k

then q = 100 * (50 ×10^-2)² / 9×10^9 = 2.777777778×10^-9 C

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