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3 years ago

Fe2O3+2Al=Al2O3+2Fe

2 answers:

6 0

We determine the limiting reactant by using the moles present in the equation and the actual moles.
According to equation, ratio of Fe₂O₃ : Al = 1 : 2
Actual moles of Fe₂O₃ = 187.3 / (56 x 2 + 16 x 3)
= 1.17
Actual moles of Al = 94.51 / 27
= 3.5
Fe₂O₃ is limiting. Fe₂O₃ required:
(moles Al)/2 = 3.5/2 = 1.75
Moles to be added = 1.75 - 1.17
= 0.58
Mass to be added = moles x Mr
= 0.58 x (56 x 2 + 16 x 3)
= 92.8 grams

Studentka2010 [4]3 years ago

4 0

92.41g, this is the correct answer

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2 years ago

A chemist prepares a solution of zinc oxalate by measuring out of zinc oxalate into a volumetric flask and filling the flask to

anyanavicka [17]

<u>Answer:</u> The concentration of zinc oxalate is $1.7\times 10^{-11}M$

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To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$

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Putting values in above equation, we get:

$\text{Molarity of solution}=\frac{7.5\times 10^{-9}\times 1000}{450mL}\\\\\text{Molarity of solution}=1.66\times 10^{-11}M=1.7\times 10^{-11}M$

In case of multiplication and division, the number of significant digits is taken from the value which has least precise significant digits. Here, the least precise number of significant digits are 2.

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3 years ago

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Answer: But because part 2 stays the same

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4 years ago

Read 2 more answers