C) They have a large number of rods and small number of cones.
Answer:
0.55 mol Au₂S₃
Explanation:
Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.
1. Gather all the information in one place:
M_r: 34.08
Au₂S₃ + … ⟶ 3H₂S + …
m/g: 56
2. Calculate the moles of H₂S
Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)
= 1.64 mol H₂S
3. Calculate the moles of Au₂S₃
The molar ratio is 1 mol Au₂S₃/3 mol H₂S.
Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)
= 0.55 mol Au₂S₃
Mass and energy can not be created or destroyed, they may be able to just be converted, and neither one seems without the opposite. For this reason in closed systems, both mass and energy are conserved individually. " I hope this helps "
Answer:
The original volume of the gas is 0.001 mL
Explanation:
This easy excersise can be solved by the law for gases, about pressure and volume; the volume of a gas is inversely proportional to the pressure it exerts.
We can propose the rule by this formula:
P₁ / V₁ = P₂ / V₂
We replace data given: 1.50 atm / V₁ = 0.50 atm / 750 mL
As the rule says, that volume is inversely proportional, and the pressure was decreased, volume must be lower than 750 mL.
1.5atm / (0.5 atm / 750mL) = V₁
V₁ = 0.001 mL