Answer:
41.4 s
Explanation:
Given data
- Rate constant (k): 8.42 × 10⁻² s⁻¹ at 800 °C
- Initial concentration of A ([A]₀): 5.00 M
- Concentration of A at a time t ([A]): 0.153 M
Let's consider the following reaction of first order with respect to A.
2 A ⇒ B
We can find the time that it will take for A to decrease from 5.00 M to 0.153 M using the following expression.
![ln([A]/[A]_0)=-k.t\\ln(0.153M/5.00M)=-8.42 \times 10^{-2}s^{-1} .t\\t = 41.4 s](https://tex.z-dn.net/?f=ln%28%5BA%5D%2F%5BA%5D_0%29%3D-k.t%5C%5Cln%280.153M%2F5.00M%29%3D-8.42%20%5Ctimes%2010%5E%7B-2%7Ds%5E%7B-1%7D%20%20%20.t%5C%5Ct%20%3D%2041.4%20s)
Answer:
the answer is longgitudinal
Group 17 is the most readily reduced elements on the periodic table, meaning that they are so close to being a stable elements, only missing 1 electron to complete their valance electron shell. Thus they will essentially react with anything to get that last electron!
Group 1 elements are extremely reactive because they are the most readily oxidized, they are very close to reaching stability by giving up only 1 electron. Thus they will react with almost anything to give up their electron.
Answer:
The correct answer is 6.265 M.
Explanation:
To find the molarity of the solution, we first must recall that molarity represents the number of moles of solute divided by the number of liters of solution. Thus, our first step should be to convert the solute amount in grams to moles, using the given molar mass.
266.07 g * (1 mol/169.88 g) = 1.5662 mol
Now, we can find the molarity using the following formula:
Molarity = moles solute/liters solution
M = 1.5662 mol/0.25 L
M = 6.265 M
Therefore, the molarity of the solution is 6.265 M.
Hope this helps!
Answer:
6.02 × 10²³ atoms.
Explanation:
According to the Avogadro number, the one mole of any substance have 6.02 × 10²³ atoms.
The number 6.02 × 10²³ is called Avogadro number. it is the number of atoms, ions or molecules in one gram atoms of element, one gram ions of substance or one gram molecules of a compound.
For one mole of magnesium.
24.305 g of Mg = 1 mole of magnesium = 6.02 × 10²³ atoms of magnesium.
Other example includes:
18 g of water = one mole of water = 6.02 × 10²³ molecules of water.
23 g of sodium = one mole of sodium = 6.02 × 10²³ atoms of sodium.
