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Nostrana [21]
3 years ago
10

Plz help. Dora calculated the mean absolute deviation for the data set 35, 16, 23, 42, and 19. Her work is shown below. Step 1:

Find the mean. mean = StartFraction 35 + 16 + 23 + 42 + 19 Over 5 EndFraction = 27 Step 2: Find each absolute deviation. 8, 11, 4, 15, 8 Step 3: Find the mean absolute deviation. M A D = StartFraction 8 + 11 + 4 + 15 Over 5 EndFraction = 9.5 What is Dora’s error?
A. Dora should have divided by 4 when finding the mean

B. Dora found the absolute deviation of 35 incorrectly

C. Dora used only four numbers in finding the mean

D. Dora used only four numbers in finding the mean absolute deviation
Mathematics
1 answer:
blondinia [14]3 years ago
7 0

Answer:

step 3 is wrong

Step-by-step explanation:

i know it because i did the unit test review

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A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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