Answer:
v2 = 65 m/s
the speed of the water leaving the nozzle is 65 m/s
Explanation:
Given;
Water flows at 0.65 m/s through a 3.0 cm diameter hose that terminates in a 0.3 cm diameter nozzle
Initial speed v1 = 0.65 m/s
diameter d1 = 3.0 cm
diameter (nozzle) d2 = 0.3 cm
The volumetric flow rates in both the hose and the nozzle are the same.
V1 = V2 ........1
Volumetric flow rate V = cross sectional area × speed of flow
V = Av
Area = (πd^2)/4
V = v(πd^2)/4 ....2
Substituting equation 2 to 1;
v1(πd1^2)/4 = v2(πd2^2)/4
v1d1^2 = v2d2^2
v2 = (v1d1^2)/d2^2
Substituting the given values;
v2 = (0.65 × 3^2)/0.3^2
v2 = 65 m/s
the speed of the water leaving the nozzle is 65 m/s
Answer:
Velocidad final, V = 40 m/s
Explanation:
Dados los siguientes datos;
Aceleración = 5 m/s²
Velocidad inicial = 0 m/s (ya que comienza desde el reposo)
Tiempo = 8 segundos
Para encontrar la velocidad final, usaríamos la primera ecuación de movimiento;
Dónde;
- V es la velocidad final.
- U es la velocidad inicial.
- a es la aceleración.
- t es el tiempo medido en segundos.
Sustituyendo en la fórmula, tenemos;

<em>Velocidad final, V = 40 m/s</em>
Cations are formed by losing electrons
Cations are basically positive ions
It's not lose or gain protons because atoms can't lose or gain protons. The protons don't move.
It's not gain electrons because electrons are negative. More electrons=more negative
If you can't remember cations are positive
CAT-ions are PAWS-itively charged
Answer:
Average speed of car in the first trip is 10 km/hr
Explanation:
It is given that first the car drives 6 hours to the east
Then travels 12 km to west in 3 hours
Average speed for the entire trip = 8 km/hr
Total time = 3+6 = 9 hour
So distance traveled in 9 hour = 9×8 = 72 km
As the car travel 12 km in west so distance traveled in east = 72-12 = 60 km
Time by which car traveled in east = 6 hour
So speed 
So average speed of car in the first trip is 10 km/hr
Equilibrium is the answer because they are reaching an equal temperature