Question

I NEED HELP PLEASE, THANKS! :)

Answer 1

Answer:

Here's what I get  

Step-by-step explanation:

In ∆s ABC and DAC

AB = DB

AC = DC

BC is common.

∴ ∆ABC ≅ ∆DBC

This is because of the SSS congruency rule, which states,

If three sides of one triangle are equal to the corresponding sides of another triangle, then the triangles are congruent.

Answer 2

Answer:

ΔABC ≅ ΔDBC

Step-by-step explanation:

Based on the information given, you can see that the triangles have 2 corresponding congruent sides with one another because of the congruent dashes on them.

This means that side AB and side BD are congruent. Also, side AC and side DC are congruent as well. Lastly, you know there is another congruent side, being side BC, this is because the triangles both share the same side, meaning they are congruent.

Since there are 3 congruent corresponding sides, this is the Side-Side-Side Theorem.