In triangle ABC, if sin A= 4/5 and tan A= 4/3, the what is cos A? 3/5 4/5 3/4 5/3
1 answer:
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Answer:
8πcm²/sec
Step-by-step explanation:
The radius of the circle increases at a rate of dr/dt = 0.25cm/sec
The radius of the circle r = 16cm
The area of the circle increases at a rate of dA/dt = ?
Area of a circle = πr²
We take the derivative with respect to t
dA/dt = 2πrdr/dt
dA/dt = 2 π (16)(0.25)
dA/dt = 8πcm²/sec
Thank you!!!
