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zloy xaker [14]
3 years ago
8

Which of the following constants can be added to x2 + x to form a perfect square trinomial?

Mathematics
1 answer:
agasfer [191]3 years ago
8 0

Answer:

x^2+x + 1/4

Step-by-step explanation:

x^2+x

Take the coefficient of x

1

divide by 2

1/2

Square it

(1/2)^2 = 1/4

Add this to make a perfect square trinomial

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A tank 4/5 full needs 75 litres to fill it up.how many litres does it hold when full
Ann [662]
X - the volume of the tank

\frac{4}{5}x+75=x \\
75=x-\frac{4}{5}x \\
75=\frac{1}{5}x  \ \ \ |\times 5 \\
x=375

The tank holds 375 liters when full.
8 0
3 years ago
Nevaeh had 12 blue pencils and 18 red pencils to give out equally among the maximum number of classmates. How many red pencils w
marissa [1.9K]

Answer:

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8 0
3 years ago
X-42=-33 what is the solution ?
bogdanovich [222]
X = -33 + 42
x = 42 - 33
x = 9
5 0
3 years ago
Read 2 more answers
If the variance of a probability was computed to be 3.6 grams, what is the standard deviation
stiks02 [169]
The standard deviation is the square root of the variance
so if the variance is 3.6, the standard deviation is the sqrt 3.6...
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4 0
3 years ago
If XY × 8 = YYY, where Xand Y are digits of the numbers, then what is the value of Y?
kakasveta [241]
Given that
XY*8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY*8 = 8 (10X + Y) = 80X + 8Y
∴ 80X + 8Y = 111Y
∴ 80 X = 111Y - 8 Y
∴ 80 X = 103 Y

∴ Y = 80X/103
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 0.77 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 1.55 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 2.33 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 3.11 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 3.88 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 4.66 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 5.44 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 6.21 ⇒⇒ unacceptable

X = 9 ⇒⇒⇒ Y = 6.99 ⇒⇒ unacceptable

So, The is no value of  Y to achieve ⇒⇒ XY * 8 = YYY

================================================

I think the problem is as following:

Given that XY8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY8 = 100X + 10Y + 8
∴ 100X + 10Y + 8 = 111Y
∴ 100x + 8 = 101Y
∴ Y = (100X + 8)/101
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 1.07 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 2.06 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 3.05 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 4.04 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 5.03 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 6.02 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 7.01 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 8    ⇒⇒⇒ integer ⇒⇒ the correct answer

X = 9 ⇒⇒⇒ Y =8.99 ⇒⇒ unacceptable

So, The value of Y = 8
8 0
3 years ago
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