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NARA [144]
3 years ago
6

Why is it that some people get a static shock when they walk across the carpet and touch a metal surface?

Chemistry
1 answer:
podryga [215]3 years ago
8 0

Answer:

This happens because there was an electric charge.

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based on the cause and effect relationship between the magnets, which phenomenon is the teacher modeling for her students.
faltersainse [42]

Answer:

Someone breaking up.

Explanation:

8 0
2 years ago
How many moles are in 187.54 grams of magnesium chlorate?
Svetlanka [38]

Hey there!

Magnesium chlorate: Mg(ClO₃)₂

Find molar mass.

Mg: 1 x 24.305 = 24.305

Cl: 2 x 35.453 = 70.906

O: 6 x 16 = 96

------------------------------------

                      191.211 g/mol

We have 187.54 grams.

187.54 ÷ 191.211 = 0.9808

There are 0.9808 moles in 187.54 grams of magnesium chlorate.

Hope this helps!

3 0
4 years ago
Are the particles moving faster or slower as time goes on? (Diagram F)
klasskru [66]
I YHINK ITTTSSS SHMMM BBBBB
4 0
3 years ago
What is mb for CH3NH2….
drek231 [11]

Answer:

A.) K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

Explanation:

The general Kb expression is:

K_b = \frac{[HA][OH^-]}{[A^-]}

In this equation

-----> Kb = equilibrium constant

-----> [HA] = acid

-----> [A⁻] = base

Since liquids are not included in equilibrium expressions, H₂O should not be present. The products are in the numerator while the reactant are in the denominator. In this reaction, CH₃NH₂ is acting as a base and CH₃NH₃⁺ is acting as an acid.

As such, the expression is:

K_b = \frac{[CH_3NH_3^+][OH^-]}{[CH_3NH_2]}

7 0
2 years ago
In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
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