1,000 millimeters is the same as ____

The initial reaction rate for the elementary reaction 2A + B → 4C was measured as a function of temperature when the concentrati

Artist 52 [7]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a) The activation energy is 124.776 $\frac{kJ}{mole}$

b) The frequency factor is 1.77 × $10^{18}$

c) The rate constant is 0.00033 $(\frac{dm^{3} }{mole} )^{2}$ $\frac{1}{s}$

Explanation:

From the question the elementary reaction for A and B is given as

2A + B → 4C

The rate equation the elementary reaction is

- $r_{A}$ = $k$ $[A]^{2}$ $[B]$

= $k[2]^{2}[1.5]$

= 6k

$k = \frac{-r_{A} }{6}$

When temperature changes, the rate constant change an this causes the rate of reaction to change as shown on the second uploaded image.

The relationship between temperature and rate constant can be deduced from these equation

$k = Aexp(-\frac{E_{a} }{RT} )$

taking ln of both sides we have

$lnk =ln A - (\frac{E_{a} }{R}) \frac{1}{T}$

Considering the graph for the rate constant $ln k$ and $(\frac{1}{T} )$ the slope from the equation is $-(\frac{E_{a} }{R})$ and the intercept is $ln A$

From the given table we can generate another table using the equation above as shown on the third uploaded image

The graph of $ln k$ vs $(\frac{1}{T} )$ is shown on the fourth uploaded image

From the graph we can see that the slope is $-(\frac{E_{a} }{R} ) = - 15008$

Now we can obtain the activation energy $E_{a}$ by making it the subject in the equation also generally R which is the gas constant is $8.145 \frac{J}{kmole}$

$E_{a} = 15008 × 8,3145\frac{J}{molK}$

$= 124\frac{KJ}{mole}$

Hence the activation energy is $= 124\frac{KJ}{mole}$

b) From the graph its intercept is $ln A = 42.019$

$A = exp(42.019)$

$=1.77 × 10^{18}$

Hence the frquency factor A is $=1.77 × 10^{18}$

c) From the equation of rate constant

$lnk =ln A - (\frac{E_{a} }{R}) \frac{1}{T}$

We have

$ln k = 42.019 - 15008 * (\frac{1}{300} )$

$k = 0.00033(\frac{dm^{3} }{mole} )^{2} \frac{1}{s}$

Hence the rate constant is $k = 0.00033(\frac{dm^{3} }{mole} )^{2} \frac{1}{s}$

6 0

3 years ago

Which two factors must be considered when predicting whether two substances will dissolve in each other?

r-ruslan [8.4K]

The two factors must be considered when predicting whether two substances will dissolve in each other are type of bonds and size of the molecules are two factors.

<h3>What is solubility?</h3>

Solubility is the ability of solute particles to dissolve in any solvent, and solubility is directly proportional to the dissolving ability of the solute.

Solubility of any substance depends on the type of the bond present in the solute molecule i.e. polar or non polar. And it is also depends on the size of the solute as size defines the surface tenssion of the substance.

Number of bonds and shape of molecules are also define the solubility but not at that extent as their type and shape.

Hence type of bonds and size of the molecules are two factors.

To know more about dissolution, visit the below link:
brainly.com/question/26073928

6 0

2 years ago

How are subtances dissolved ?

ELEN [110]

Answer: A solute dissolves because its particles interact with the particles of a solvent. Anything that allows more solvent to touch more solute will cause a solute to dissolve more quickly. Small pieces of a substance dissolve faster than large pieces.

3 0

4 years ago

Read 2 more answers

Given 1 cm3 = 1 mL What is the volume in cubic centimeters of a 500 ml beaker? cm3

makvit [3.9K]

Answer:

500 cubic centimeters of water

3 0

3 years ago

Read 2 more answers

The forensic technician at a crime scene has just prepared a luminol stock solution by adding 15.0 gg of luminol into a total vo

Firdavs [7]

Answer:

1.13 M

Explanation:

Given data

Mass of luminol (solute): 15.0 g

Volume of solution = volume of water = 75.0 mL = 0.0750 L

Molar mass of luminol: 177.16 g/mol

The molarity of the stock solution of luminol is:

M = mass of solute / molar mass of solute × liters of solution

M = 15.0 g / 177.16 g/mol × 0.0750 L

M = 1.13 M

6 0

3 years ago

1,000 millimeters is the same as _____