Answer:
to calculate the molarity of the said sucrose,
firstly calculate the moles
which is = Molecular weight of C12H22O11 = 342g/mol
then
moles = 139/342
= 0.41 moles
to calculate Molarity now
Molarity= moles of the solute/volume of solution in liter
=0.41/2.60
=0.158M
Explanation:
Answer:
I think this would be iron
Explanation:
The mass of nitroglycerin : 34.52 g
<h3>Further explanation</h3>
Reaction
4C₃H₅N₃O₉ ⇒ 12 CO₂ + 10H₂O + 6N₂ +O₂
Volume = 10 L
Temperature = -5°C=268 °K
Pressure = 1 atm
mol of CO₂ (ideal gas) :

mol ratio C₃H₅N₃O₉ : mol CO₂= 4 : 12, so mol C₃H₅N₃O₉ :

mass C₃H₅N₃O₉ (MW=227,0865 g/mol):

Answer:
0.053 M is the concentration of X after 196 seconds.
Explanation:
Initial concentration of the X =
Time taken by the sample, t = 196 s
Final concentration of the X after t = [A] =?
Rate constant of the reaction = k = 
Formula used :
![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
where,
Now put all the given values in this formula, we get
![[A]=[1.0M]\times e^{-1.50\times 10^{-2} s^{-1}\times 196 s}](https://tex.z-dn.net/?f=%5BA%5D%3D%5B1.0M%5D%5Ctimes%20e%5E%7B-1.50%5Ctimes%2010%5E%7B-2%7D%20s%5E%7B-1%7D%5Ctimes%20196%20s%7D)
![[A]=0.053 M](https://tex.z-dn.net/?f=%5BA%5D%3D0.053%20M)
0.053 M is the concentration of X after 196 seconds.