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Elden [556K]
3 years ago
9

A nurse practitioner is studying the effects of sugary drinks on weight gain. To begin the study, the nurse practitioner asks a

random sample of patients how many sugary drinks they consume in one day. Each person is asked to report a whole number. The results of the survey are shown in this relative frequency histogram. Relative frequency histogram of number of sugary drinks consumed in one day. There are seven bins of discrete values ranging from 0 to 6. The relative frequencies of the bins from left to right are 0.07, 0.02, 0.01, 0.30, 0.06, 0.22, and 0.32. Determine the median number of sugary drinks consumed in one day by the patients sampled in the survey.
Mathematics
1 answer:
Mrac [35]3 years ago
7 0

The median number of sugary drinks consumed in one day by the patients sampled in the survey is 0.07

Given the required relative frequencies of the bins from left to right as shown;

0.07, 0.02, 0.01, 0.30, 0.06, 0.22, and 0.32

  • The median of the data is the value that falls in the middle after rearrangement either in ascending or descending order.

Re-rrange the data in ascending order

0.01, 0.02, 0.06), 0.07, (0.22, 0.30, 0.32

After re-arranging we can see that the median number of sugary drinks consumed in one day by the patients sampled in the survey is 0.07

Learn more here: brainly.com/question/7730356

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Surface area of a 4m and 4m and 4m cube
jeka94

Answer: 96 m²

Step-by-step explanation: Surface area is the sum of the areas of all of the faces of a 3-dimensional figure.

So to find the surface area of a cube, it's important to understand that each face of a cube has the same area so we can simply find the area of one face of a cube and multiply by the number of faces which is 6.

To find the area of one face of a cube, we can use the formula for the area of a square which is S².

Since the length of a side is 4 meters, we have (4 m)² or 4 meters x 4 meters which is 16 m².

Now, since there are six sides to a cube, we have 6 (16 m)² which is equal to 96 m². So the surface area of the cube is 96 m².

6 0
3 years ago
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After being rejected for employment, Kim Kelly learns that the Bellevue Credit Company has hired only three women among the last
mixer [17]

Answer:

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

Step-by-step explanation:

For each employee hired, the are only two possible outcomes. Either it is a man, or it is a woman. The probability of a person hired being a man or a woman is independent of any other person. This means that we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

21 new employees.

This means that n = 21

She also learns that the pool of applicants is very large, with an approximately equal number of qualified men as qualified women.

This means that p = 0.5

Help her address the charge of gender discrimination by finding the probability of getting three or fewer women when 21 people are hired.

This is

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{21,0}.(0.5)^{0}.(0.5)^{21} \approx 0

P(X = 1) = C_{21,1}.(0.5)^{1}.(0.5)^{20} = 0.00001

P(X = 2) = C_{21,2}.(0.5)^{2}.(0.5)^{19} = 0.0001

P(X = 3) = C_{21,3}.(0.5)^{3}.(0.5)^{18} = 0.0006

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0 + 0.00001 + 0.0001 + 0.0006 = 0.00071

0.00071 = 0.71% probability of getting three or fewer women when 21 people are hired. This probability, which is very small, supports the charge of gender discrimination.

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Answer:

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Answer:

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The statistical question would be B.

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