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NISA [10]
4 years ago
15

Write in radical form and simplify if possible: (5x)⅓

Mathematics
1 answer:
Llana [10]4 years ago
4 0

Answer: \sqrt[3]{5x}

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F(x) = 3x + 2<br> What is f(5)?<br><br> PLEASE HELP!!!!
abruzzese [7]
Resolving a function of any nature means determining your zeros or raizes.

The zeros of a function occur when the function is null.

Then:

f(x) = 3x - 2

To determine the root
f(x) = 0 = 3x - 2
3x = 2
x = 2/3 Final result
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Point A is the incenter of ΔDEF. Point A is the incenter of triangle D E F. Lines are drawn from the points of the triangle to p
Trava [24]

Answer:

9 points

Step-by-step explanation:

took the quiz edge2020

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The lengths of text messages are normally distributed with a population standard deviation of 4 characters and an unknown popula
umka21 [38]

Answer:

The answer is "(25.32, 30.68)"

Step-by-step explanation:

Given:

\bar x = 28\\\\ \sigma = 4\\\\n =26\\\\

When 98\% confidence level so, the z:

\alpha = 1 - 98\% = 1 - 0.98 = 0.2\\\\\frac{\alpha}{2} =\frac{0.02}{2} = 0.01\\\\Z_{\frac{\alpha}{2}} = Z_{0.01} = 1.645\ \ \  ( Using \ z \ table )\\\\

E = Z_{\frac{\alpha}{2} \times ( \frac{\sigma}{\sqrt{n}})  

= 1.645 \times (\frac{4}{\sqrt{26}})\\\\=2.68

When  98% confidence interval estimate of the population mean  is,

\bar x - E < \mu < \bar x + E\\\\28 - 2.68 <  \mu < 28 + 2.68\\\\25.32 <  \mu < 30.68\\\\(25.32,  30.68)\\\\

7 0
3 years ago
Please help:((((((((((
Jet001 [13]

Answer:

7. 3x + 6 = 3x + 10

8. 3x + 6 = x + 2(x + 3)

Step-by-step explanation:

7.

To write an equation with no solutions, we write an equation in which the x terms are eliminated, and we end up with a false statement when we try to solve the equation.

Start with

3x + 6 =

This means: take a number, x, multiply it by 3, then add 6 to it.

To make it into an impossible equation, take the same number x, multiply it by 3, and now add 10 instead of 6. The same number x, multiplied by 3 just like above, and now with 10 added to it cannot equal 3x + 6.

Let's write the equation and try to solve it.

3x + 6 = 3x + 10

Subtract 3x from both sides.

6 = 10

Since 6 = 10 is a false statement, there is no solution.

8.

Now we need an equation that is true for every value of x.

We start with 3x + 6 on the left side.

3x + 6 =

To make it true for every value of x, which means it has an infinite number of solutions, we write an expression on the right side that is the same as 3x + 6, just written in a different form.

For example, start with

3x + 6

Separate 3x into x + 2x, now you have

x + 2x + 6

Now factor 2 out of 2x + 6, so you get

x + 2(x + 3)

The expression x + 2(x + 3) is equal to the expression 3x + 6. Now we use x + 2(x + 3) on the right side of the equation we are writing. We get:

3x + 6 = x + 2(x + 3)

Let's solve this equation.

Distribute on the right side.

3x + 6 = x + 2x + 3

Combine like terms on the right side.

3x + 6 = 3x + 6

Subtract 6 from both sides.

3x = 3x

Subtract 3x from both sides.

0 = 0

0 = 0 is a true equation. Therefore, the equation 3x + 6 = x + 2(x + 3) has infinitely many solutions. in other words, every real number is a solution of the equation.

8 0
3 years ago
In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two tr
Deffense [45]

XZ ≅ EG and YZ ≅ FG is enough to make triangles to be congruent by HL. Option b is correct.

Two triangles ΔXYZ and ΔEFG, are given with Y and F are right angles.

Condition to be determined that proves triangles to be congruent by HL.

<h3>What is HL of triangle?</h3>

HL implies the hypotenuse and leg pair of the right-angle triangle.

Here, two right-angle triangles ΔXYZ and ΔEFG are congruent by HL only if their hypotenuse and one leg are equal, i.e. XZ ≅ EG and YZ ≅ FG respectively.

Thus, XZ ≅ EG and YZ ≅ FG are enough to make triangles congruent by HL.

Learn more about HL here:

brainly.com/question/3914939

#SPJ1

In ΔXYZ and ΔEFG, angles Y and F are right angles. Which set of congruence criteria would be enough to establish that the two triangles are congruent by HL?

A.

XZ ≅ EG and ∠X ≅ ∠E

B.

XZ ≅ EG and YZ ≅ FG

C.

XZ ≅ FG and ∠X ≅ ∠E

D.

XY ≅ EF and YZ ≅ FG

8 0
2 years ago
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