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Sever21 [200]
3 years ago
6

If a spring has a spring constant of 2 N/m and it is stretched 5 cm, what is the force of the spring?

Physics
1 answer:
Lerok [7]3 years ago
5 0

Answer:

0.1 N

Explanation:

Considering that Hooke's law, F=xk where k is the spring constant in N/m, x is extension in meters, F is spring force in N.

Converting the given extension from cm to m, we divide by 100 hence 5/100=0.05 m

Substituting 0.05 m for x and 2 N/m for k then the spring force will be

F=2*0.05=0.1 N

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Knowing the ME is the total energy, we add up the energies of the system. Since it is being influenced by the Earth, as per the problem stating the satellite has circular orbit around the Earth, we know there is gravitational potential. Since it is orbiting, we can assume some type of velocity. Nothing else that we need to worry about should be occuring at this level of physics, leaving you with

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this should give us

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since there is a negative being subracted, we can change that to

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Answer:

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Explanation:

Given,

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The force acting on the body, F = 657.9 N

The force acting on an object is proportional to the product of mass and acceleration of the body.

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Therefore, the acceleration of the body is

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