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3 years ago

Light wands are small tubes that can be used to give off light without electricity or fire.

Physics

2 answers:

crimeas [40]3 years ago

8 0

i just had this question, "the chemical energy of the fluids inside the wand"

miv72 [106K]3 years ago

4 0

<span>c.the chemical energy of the fluids inside the wand</span>

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A makes an angel of 30.0 above the positive x-axis, and B makes an angel of 45.0 below the negative x-axis. A=3.00 units and B=2

erik [133]

I think this is vectors. Sketch the two vectors A and B on the x axis and then find their magnitudes using cosine... i would like to know if i am correct.

5 0

3 years ago

The diagram shows a ball resting at the top of a hill.

WARRIOR [948]

Answer:

a) The potential energy in the system is greatest at X.

Explanation:

Let be X the point where a ball rests at the top of a hill. By applying the Principle of Energy Conservation, the total energy in the physical system remains constant and gravitational potential energy at the top of the hill is equal to the sum of kinetic energy, a lower gravitational energy and dissipated work due to nonconservative forces (friction, dragging).

$U_{grav, X} = U_{grav, Y} + K_{Y} + \Delta W_{X \rightarrow Y} = U_{grav,Z}+\Delta W_{X \rightarrow Z}$

Conclusions are showed as follows:

a) The potential energy in the system is greatest at X.

b) The kinetic energy is the lowest at X and Z.

c) Total energy remains constant as the ball moves from X to Y.

Hence, the correct answer is A.

7 0

3 years ago

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19. When baking soda and vinegar are combined, the result is a salt called sodium acetate. This forms

Orlov [11]

It is a chemical change because the baking soda and vinegar are reacting to form a new product.

3 0

3 years ago

A point charge q1 = 3.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 10 m.

UkoKoshka [18]

Answer:

a) 1.6 mN b) -1.6 mN c) -1.6 mN d) 1.6 mN

Explanation:

The electrostatic force between 2 point charges, obeys the Coulomb's Law, that can be expressed as follows:

F₁₂ = k*q₁*q₂/(r₁₂)² (in magnitude)

The direction of the force, is along the line that joins the charges (along the x axis) and as q₁ and q₂ are of the same sign, aims away from both charges.

a) So, for the force on q₂, we have:

F₁₂ = 9*18*10⁻⁵ N = 1.6 mN (positive as it is aiming in the positive x direction)

b) The force on q1, according to Newton's 3rd Law, is just equal and opposite to the one on q2:

F₂₁ = (-9*18*10⁻⁵) N = -1.6 mN (towards the negative x direction, away from q1)

c) If q₂ were -6.0 μC, the force will be the same in magnitude, but as now both charges have different signs, they wil attract each other, so the direction of the forces will be exactly the opposite to the first case:

F₁₂ = -1.6 mN (going towards the origin, where q₁ is located)

F₂₁ = 1.6 mN (going in the positive x direction, towards q₂)

6 0

4 years ago

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An electric motor draws out 5 A of current from a 20 V battery. How much power is it using?

irinina [24]

Answer:

Explanation:

P = VI = 20(5) = 100 W

7 0

3 years ago

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