<span>The momentum of the falcon before collision is 0.6 * 20 = 12000 kgm/s which is actually the momenum of the falcon in the x-component. I had converted 600g to kg. After the collision the x-component of the raven is now mv2cos(thetha) where v2 is the final velocity of the raven and theta is the angle at which the falcon hits the raven. So we have that the falcon's final velocity = 600 * 5 * cos (theta). Likewise, after getting hit the the falcon, the raven's final momentum of is = m2v2cos(theta) = 1.5 * 9 * cos(theta). There's no motion along the y-components. So equating we have, momentum before collision = momentum after collision of the raven + momentum after collision of the falcon.
So we have 12000 = 3000cos(theta) + 13.5cos(theta). Cos(theta)(3000 + 13.5) = 12000. Theta = cos^-1( 12000/3013.5 = 3.98 So theta =</span>
The answer of this question is B. 22x + 20
Answer:
30 N
Explanation:
there are two forces act on the bar:
- weight of 1.5 kg mass, w = mg = 15 N
- weight of the bar, wb
for balance,
w * Lw = wb * Lwb
Lw = length of bar from the mass to the pivot
Lwb = lenght of bar from the center of the bar to the pivot
15 * 20 = wb * (50-20)
300 = wb * 30
wb = 300/30 = 30 N
The expression for the block's centripetal acceleration is derived as ω²r or v²/r.
<h3>
What is centripetal acceleration?</h3>
The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.
The expression for the block's centripetal acceleration is derived as follows;
ω = dθ/dt
where;
- ω is the angular speed
- θ is the angular displacement
- t is the time of motion
ac = ω²r
where;
- r is the radius of the circular path
Also, ω = v/r
ac = (v/r)²r
ac = v²/r
Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.
Learn more about centripetal acceleration here: brainly.com/question/79801
The correct answer is false
