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suter [353]
2 years ago
12

Pls help i’ll give brainliest if you give a correct answer!!

Physics
1 answer:
enot [183]2 years ago
4 0

Answer:

the second one

Explanation:

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A uniform electric field is created by two parallel plates separated by a distance of 0.04 m. What is the magnitude of the elect
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Complete question:

A uniform electric field is created by two parallel plates separated by a

distance of 0.04 m. What is the magnitude of the electric field established

between the plates if the potential of the first plate is +40V and the second

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Answer:

The magnitude of the electric field established between the plates is 2,000 V/m

Explanation:

Given;

distance between two parallel plates, d = 0.04 m

potential between first and second plate, = +40V and -40V respectively

The magnitude of the electric field established between the plates is calculated as;

E = ΔV / d

where;

ΔV is change in potential between two parallel plates;

d is the distance between the plates

ΔV = V₁ -V₂

ΔV = 40 - (-40)

ΔV = 40 + 40

ΔV = 80 V

E = ΔV / d

E = 80 / 0.04

E = 2,000 V/m

Therefore, the magnitude of the electric field established between the plates is 2,000 V/m

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How can stretching affect the range of motion of the neck? Hypothesis
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