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3 years ago

Pls help i’ll give brainliest if you give a correct answer!!

Physics

1 answer:

enot [183]3 years ago

4 0

Answer:

the second one

Explanation:

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In the kitchen of your house you would like to run a 240 W blender, a 30 W phone charger, a 720 W toaster oven, and two 120 W li

meriva

Current pulled by these appliances is 10.25 A

Explanation:

Step 1: Find the total power used by these appliances.

Total power = 240 + 30 + 720 + (2 × 120) = 1230 W

Step 2: Given voltage is 120 V, find the current by using the formula Power = Voltage × Current

⇒ Current(I) = P/V = 1230/120 = 10.25 A

8 0

3 years ago

DUE TONIGHT HURRY PLS I give 30 pts

Paha777 [63]

The answer is both.

For kinetic energy:

KE = 1/2*m*v^2 = 0.5*20,000 grams*5 = 50,000 J

For gravitational potential energy:

Pe = mgh = 20,000 grams*9.81 m/s^2*2 m = 392.2 J

6 0

4 years ago

Satellite A orbits a planet at a distance d from the planet’s center with a centripetal acceleration a0. A second identical sate

leva [86]

To solve this problem it is necessary to use the concepts related to the Gravitational Force and Newton's Second Law, as far as we know:

$F_g = \frac{GMm}{r^2}$

Where,

G = Gravitational constant

M = Mass of earth (in this case)

m = mass of satellite

r = radius

In the other hand we have the second's newton law:

$F = ma$

Where,

m = mass

a = acceleration

Equation both equations we have,

$ma = \frac{GMm}{r^2}$

For the problem we have that,

Satellite A:

$ma_A = \frac{GMm}{r^2}$

Satellite B:

$ma_B = \frac{GMm}{(2r)^2}$

The ratio between the two satellites would be,

$\frac{ma_A}{ma_B}= \frac{\frac{GMm}{r^2}}{\frac{GMm}{(2r)^2}}$

Solving for a_B,

$a_B = \frac{a_A}{4}$

Therefore the centripetal acceleration of $A_B$ is a quarter of $a_A$

7 0

3 years ago

a sound wave travels at 330 m/sec and has a wavelenght of 2meters. calcuate the frequency and period

Sergio039 [100]

The frequency of any wave is (speed) / (wavelength).

Frequency = (330 m/s) / (2m) = 165 per second = 165 Hz.

Period = 1 / frequency = 1 / (165 per second) = 0.0061 second 

7 0

3 years ago

A 0.50 kg object is at rest. A 2.88 N force to the right acts on the object during a time interval of 1.48 s. a) What is the vel

Murljashka [212]

Answer:

8.5m/s

Explanation:

We are given that

Mass of object=m=0.50 kg

Initial velocity, u=0

Force=F=2.88 N

Time=1.48 s

a.We know that

$F=ma$

Using the formula

$2.88=0.50a$

$a=\frac{2.88}{0.50}=5.76m/s^2$

$a=\frac{v-u}{t}$

Using the formula

$5.76=\frac{v-0}{1.48}$

$v=5.76\times 1.48=8.5m/s$

Hence, the velocity of the object at the end of this time interval=8.5m/s

8 0

3 years ago