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galina1969 [7]
2 years ago
10

A scientist launches a 100 g ball from a catapult as part of an experiment. The ball travels at 500 m/s after launch. The catapu

lt weighs 2,000 g and has a slight recoil. Which relationship best describes the recoil of the catapult
Physics
1 answer:
Umnica [9.8K]2 years ago
7 0

Answer:

V₂ = - m₁ V₁ / m₂

Explanation:

According to law of conservation of momentum, "Total momentum of an isolated system remains constant. i.e

Pi = Pf

We consider ball and catapult an isolated system.

before launching ball momentum of the system is zero.

After launching ball momentum of ball is:

Pb= 0.1 * 500 = 50 kg m/s

Now according to law of conservation of momentum:

Pf = Pi

⇒ Pb + Pc = 0

Let Pb= m₁ V₁

&    Pc = m₂ V₂

So

m₁ V₁ + m₂ V₂ = 0

⇒ V₂ = - m₁ V₁ / m₂

The negative sing shows that catapult velocity will have opposite direction to the ball velocity.

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A racing car has a mass of 750 kg. It undergoes an acceleration of 4.00 m/s2. What is the net force acting on the car?
navik [9.2K]

Answer:

<h2>3000 N</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 750 × 4 = 3000

We have the final answer as

<h3>3000 N</h3>

Hope this helps you

3 0
2 years ago
I was driving 150 km/hr for 20 km, then had to pull over for a quarter of an hour to replace my tire, and then drove the last 3.
Likurg_2 [28]

Answer:

ertyu

Explanation:

4 0
3 years ago
When you drop a ball it accelerates downward at 9.8 m/s^2. If instead you 5 points
dangina [55]

Answer:

if you need an actual number answer you can use   :Vf = Vi + at.  If you throw the ball it will have an initial force beside gravity accelerating the fall temporarily from greater than throw it downwards, its acceleration (in the absence of air resistance) will be greater than  9.8 m/s2 until it slows back down to a constant 9.8 m/s2 after ( t )amount of time

Explanation:

If you drop a ball, it accelerates downward at 9.8 m/s2. if instead you throw the ball straight downwards While throwing, we apply an additional force other than the gravitational force.

This gives an additional, temporary acceleration along with the gravitational acceleration.

Thus from the instant it is thrown and the instant it leaves your hand, the object is under variable acceleration, the variation of acceleration being the reason of the varying force which we do apply on the object. But once it leaves our hand it is always under constant acceleration of g which is9.8 m/s2

5 0
2 years ago
Suppose that the linear density of the A string on a violin is 8.20 10-4 kg/m. A wave on the string has a frequency of 410 Hz an
alukav5142 [94]

Answer:

T = 69.49 N

Explanation:

The relation between the tension and speed of a wave is:

v=\sqrt{\frac{T}{\mu}} (1)

Where:

  • T is the tension of the string
  • μ is the linear density (8.20*10⁻⁴ kg/m)
  • v is the speed of the wave

Let's recall, that the speed of a wave is the wavelength times the frequency, so:

v=\lambda *f=0.71*410=291.1 m/s

Now, we just need to solve the equation (1) for T and use the value of v we found before.

T=\mu v^{2}=8.20*10^{-4}*(291.1)^{2}=69.49 N

Therefore the tension of string is 69.49 N.

I hope it helps you!

4 0
2 years ago
When waves traveling in the same medium meet, a new
hammer [34]

Answer:

if there is any phase between the waves this value is less

if the sine function is ±, the amplitude of the total wave is

               A_total = A₁ + A₂ + A₃+ A₄ +A₅

Explanation:

When several waves travel in the same direction, the process of adding them can take place.

               y_total = ∑ y_{i}

     where

         y_{i} = A_{i} sin (k x - w t + Ф)

with fi the phase of each wave

       To produce the largest possible result, all waves must come with the same phase

                y_total = (A₁ + A₂ + A₃ + A₄ + A₅) sin (k x - wt)

if there is any phase between the waves this value is less

if the sine function is ±, the amplitude of the total wave is

               A_total = A₁ + A₂ + A₃+ A₄ +A₅

8 0
3 years ago
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