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3 years ago

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A scientist launches a 100 g ball from a catapult as part of an experiment. The ball travels at 500 m/s after launch. The catapu

lt weighs 2,000 g and has a slight recoil. Which relationship best describes the recoil of the catapult

1 answer:

Umnica [9.8K]3 years ago

7 0

Answer:

V₂ = - m₁ V₁ / m₂

Explanation:

According to law of conservation of momentum, "Total momentum of an isolated system remains constant. i.e

Pi = Pf

We consider ball and catapult an isolated system.

before launching ball momentum of the system is zero.

After launching ball momentum of ball is:

Pb= 0.1 * 500 = 50 kg m/s

Now according to law of conservation of momentum:

Pf = Pi

⇒ Pb + Pc = 0

Let Pb= m₁ V₁

& Pc = m₂ V₂

So

m₁ V₁ + m₂ V₂ = 0

⇒ V₂ = - m₁ V₁ / m₂

The negative sing shows that catapult velocity will have opposite direction to the ball velocity.

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