Answer:
or 
Step-by-step explanation:
step 1
Find the total distance on a map between Smithville to Clarksville

step 2
Find the actual distance
The scale on a map is equal to 
Applying proportion

Convert to mixed number

Answer:
assuming the bracket is a one, it would be y=1x+/-_(any number other than 52)
Step-by-step explanation:
for example, y=1x+15
Answer:
The mean is 27.8
The required variance is 23.9358
Step-by-step explanation:
Consider the provided information.
Here the random sample size, n = 200
Unemployment rate is 13.9% = p = 0.139
Part (a) expected number of grads who are unemployed.
Hence, the mean is 27.8
Part (b) variance of the random variable "number of grads who are unemployed.

Hence, the required variance is 23.9358