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Len [333]
3 years ago
15

What is the difference between convert and concave lens In a mirror I mean

Physics
1 answer:
Phoenix [80]3 years ago
4 0

Answer:

it lies in the image formed by the two ,,,,convex forms a diminished image while concave forms a diminished or enlarged image depending on the position of the object

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A farm tractor tows a 3300-kg trailer up a 14" incline with a steady speed of 2.8 m/s. what force does the tractor exert on the
gladu [14]

The force exerted by gravity is:

F = m g

F = 3300 kg * 9.8 m/s^2

F = 32,430 N

 

The force exerted due to the inclined plane is:

F tractor = 32,430 N * sin 14

<span>F tractor = 7,823.75 N      (answer)</span>

7 0
3 years ago
A car’s momentum is p when it is traveling with a velocity of v. If the velocity of that car doubles, what is the new momentum o
lubasha [3.4K]

Answer:

∆p=(m2v)kg.m/s

Explanation:

∆p=mv where v=2v. hence ∆p=m2v

5 0
3 years ago
Read 2 more answers
A lens collects light and focuses it into a small spot. This increases the ________ of the light wave.A lens collects light and
Anika [276]

Answer:

intensity.

Explanation:

when the light collected by the lens is focused into a small spot it tends to increase the intensity of the light.

as different path of light with different intensity combines from passing through the lens it tends to make the light path and intensity coherent and after being coherent there intensity increases.

8 0
3 years ago
How does the sun create heat?
Triss [41]

Explanation:

sun was created through the hypothesis

3 0
2 years ago
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In a 400-m relay race the anchorman (the person who runs the last 100 m) for team A can run 100 m in 9.8 s. His rival, the ancho
melisa1 [442]

Answer:

largest lead = 3 m

Explanation:

Basically, this problem is about what is the largest possible distance anchorman for team B can have over the anchorman for team A when the final leg started that anchorman for team A won the race. This show that anchorman for team A must have higher velocity than anchorman for team B to won the race as at the starting of final leg team B runner leads the team A runner.

So, first we need to calculate the velocities of both the anchorman  

given data:

Distance = d = 100 m

Time arrival for A = 9.8 s

Time arrival for B = 10.1 s

Velocity of anchorman A = D / Time arrival for A

=100/ 9.8 = 10.2 m/s

Velocity of anchorman B = D / Time arrival for B

=100/10.1 = 9.9 m/s

As speed of anchorman A is greater than anchorman B. So, anchorman A complete the race first than anchorman B. So, anchorman B covered lower distance than anchorman A. So to calculate the covered distance during time 9.8 s for B runner, we use

d = vt

= 9.9 x 9.8 = 97 m  

So, during the same time interval, anchorman A covered 100 m distance which is greater than anchorman B distance which is 97 m.

largest lead = 100 - 97 = 3 m

So if his lead no more than 3 m anchorman A win the race.

5 0
3 years ago
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