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3 years ago

Apply: The earth's gravity is pulling on you. Are you pulling on the earth? Explain your

Physics

1 answer:

coldgirl [10]3 years ago

5 0

Answer:

Yes, you are pulling on Earth. Reasoning. Third Newton's law of motion, action and reaction law, sates that for every action force, there is an equal (in magnitude) and opposite reaction force.

Explanation:

goo gle.

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Tom stops using a new skin cream for five days to determine if the cream is the cause of a recent rash. What stage of the scient

jenyasd209 [6]

The ID, or Independent Variable, I think.

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4 years ago

A symmetric double-convex lens has radii of curvature equal to 11 cm. It is made from glass that has an index of refraction equa

kondaur [170]

Answer:

Chicken Legs

Explanation:

So you fry the legs into chicken:)

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3 years ago

You have arranged that the magnetic field in a particular region of space is due North with a value of 0.0040 T. An electron ent

Anna [14]

Answer:

1. Magnetic force = 4.56*10^-12 N

2. Acceleration = 5.01 *10^18 m/s^2

3. A) The direction of the moving electron will change but its speed will remain constant.

Explanation:

Given Data:

B = 0.0040 T North

q = 1.6*10^-19 C

Mass of electron = 9.1*10^-31 kg

V = 9.5% of speed of light

= 9.5% *3*10^8

= 28.5*10^6 m/s west

So, B and v are perpendicular to each other.

Therefore, ∅ = 90°

1, Calculating the magnetic force using the formula;

F = qvBsin∅

= 1.6*10^-19 * 28.5*10^6*sin90

= 4.56*10^-12 N

Therefore, the strength of the force = 4.56*10^-12 N

2. Calculating acceleration using the formula;

F = ma

a = F/m

= 4.56*10^-12 /9.1*10^-31

= 5.01 *10^18 m/s^2

3. A) The direction of the moving electron will change but its speed will remain constant.

3 0

3 years ago

What would be the kinetic energy k2q of charge 2q at a very large distance from the other charges? express your answer in terms

Pavlova-9 [17]

Answer:

$K_{2q}=\frac{7.76kq^2}{d}$

Explanation:

At the corner of the square, the potential energy of interaction of other charges with the charge 2q is given by $U_{2q}$

$U_{2q,i}=k\frac{(2q)(q)}{d}+k\frac{(2q)(5q)}{d}+k\frac{(2q)(-3q)}{\sqrt{2}d}=\frac{7.76 kq^2}{d}$

Also, since $K_{2q,i}=0$

The initial energy of the system is given by;

$E_i=U_{2q ,i}+K_{2q,i}=\frac{7.76kq^2}{d}+0=\frac{7.76kq^2}{d}$

Since $U_{2q,f}=0$

, the final energy of the system is obtained by

$E_f=U_{2q ,f}+K_{2q,f}=0+K_{2q,f}$

From the law of conservation of energy, $E_i=E_f$

Therefore, $K_{2q}=\frac{7.76kq^2}{d}$

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3 years ago

Will plane flat mirror will make a real or virtual image? Real Virtual

Galina-37 [17]

Image formed by a plane mirror is always virtual (meaning that the light rays do not actually come from the image), upright, and of the same shape and size as the object it is reflecting.

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4 years ago