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3 years ago

In comparison to radio waves, visible light has:

Physics

1 answer:

Alexxx [7]3 years ago

8 0

Answer:

Visible light has a shorter wavelength than radio waves

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Which element is likely to be the most reactive? bromine (Br) chlorine (Cl) fluorine (F) iodine (I)

RUDIKE [14]

Answer:

Fluorine is the most reactive element

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3 years ago

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A superconducting solenoid has 3300 turns per meter and can carry a maximum current of 4.1 ka. find the magnetic field strength

avanturin [10]

Hope this helps you.

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2 years ago

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A bat can detect small objects such as an insect whose size is approximately equal to the wavelength of the sound the bat makes.

slamgirl [31]

Answer:

size of insect = wavelength = 16.1 mm

Explanation:

Since the bat can detect the size of small insects which are of size equal to the wavelength of sound in air

So here we can say that the wavelength of sound is the ratio of speed of sound and its frequency

here we know that

speed of sound in air is 536 m/s

frequency of sound is 33.3 kHz

so here we can say

$\lambda = \frac{v}{f}$

$\lambda = \frac{536}{33.3 \times 10^3}$

$\lambda = 0.0161 m$

$\lambda = 16.1 mm$

7 0

3 years ago

A converging-diverging nozzle has a throat area of 10 cm2 and an exit area of 28.96 cm2 . A normal shock stands in the exit when

Svetllana [295]

The tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

The given parameters:

Throat area of the nozzle, $A^*$ = 10 cm² = 0.001 m²
The exit area of the nozzle, A = 28.96 cm² = 0.002896 m²
Air pressure at sea level = 101.325 kPa

The ratio of the areas of the converging-diverging nozzle is calculated as follows;

$= \frac{A}{A^*} \\\\= \frac{0.002896}{0.001} \\\\= 2.896$

From supersonic isentropic table, at $\frac{A}{A^*} = 2.896$ , we can determine the following;

$M_e = 2.6 \ kg/s\\\\\frac{P_o}{P_e} = 19.954$

The tank pressure is calculated as follows;

$\frac{P_o}{P_e} = 19.954 \\\\P_e = \frac{P_o}{19.954} \\\\P_e = \frac{101.325 \ kPa}{19.954} \\\\P_e = 5.08 \ kPa$

Thus, the tank pressure is 5.08 kPa and the mass flow rate is 2.6 kg/s.

Learn more about converging-diverging nozzle design here: brainly.com/question/13889483

8 0

2 years ago

If the load is 13 cm from the fulcrum, how much effort is needed to lifth the load ? Help me.

snow_tiger [21]

That depends on a few things that you haven't told us about the setup.
So I'm going to assume one of them, and then give you the answer
in terms of another one:

-- Assume a Class-I lever . . . the fulcrum is between the load and the effort.

-- Then the effort needed to lift the load is

(the weight of the load) x (13 / the distance between the fulcrum and the effort)

7 0

2 years ago