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3 years ago

Anyone know the answer ?

Physics

1 answer:

telo118 [61]3 years ago

5 0

The power supply isn't connected

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What are the names of the 2 charged particles in an atom and what are their charges

Sholpan [36]

Answer:

Protons and electrons

Explanation:

The atoms are made up of protons, neutrons, and electrons.
The physical and chemical characteristics of an atom are determined by the number of these particle composition.
The protons present in the center of an atom called the nucleus is positively charged.
The neutrons are also located in the nucleus of an atom with no charge.
The electrons has a negative charge and it is placed around the nucleus having different shells and quantum state.
The charges of the protons and electrons are denoted by +q and -q. The quantization of these charges are +1, +2, ... and -1, -2, .... etc.

3 0

2 years ago

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

5 0

3 years ago

Please help me out with these !! 50 points would greatly appreciate it.

marysya [2.9K]

Answer:

oh thank you for the free points :D

Explanation:

6 0

3 years ago

Read 2 more answers

The intensity of sunlight falling on the earth is about 1.4 kw/m2 (before any gets absorbed by our atmosphere). at what rate doe

xxTIMURxx [149]

The area of the Earth (Ae) that is irradiated by is given by:

Ae = 4πRe^2, where Re = Distance from Sun to Earth
Substituting;
Ae = 4π*(1.5*10^8*1000)^2 = 2.827*10^23 m^2

On the Earth, insolation (We) = Psun/Ae

Therefore,
Psun (Rate at which sun emits energy) = We*Ae = 1.4*2.827*10^23 = 3.958*10^23 kW = 3.958*10^26 W

6 0

3 years ago

gladu [14]

v = u + at

50 = 0 + a*10

50 = 10a

a = 5 m/s^2

4 0

2 years ago