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cupoosta [38]
3 years ago
7

Solve for x in the given triangle. A) -9 B) -7 C) 7 D) 6

Mathematics
1 answer:
Gelneren [198K]3 years ago
6 0
Wheres the triangle??
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Find the solution to x2=28
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x² = 28

x = √28

Factoring 28

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1

28 = 2.2.7 = 2².7

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7 0
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Answer:

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Simplify the radical expression.
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\bf \sqrt[4]{625x^{12}y^8}~~ \begin{cases} 625=&5\cdot 5\cdot 5\cdot 5\\ &5^4\\ x^{12}=&x^{3\cdot 4}\\ &(x^3)^4\\ y^8=&y^{2\cdot 4}\\ &(y^2)^4 \end{cases}\implies \pm\sqrt[4]{5^4(x^3)^4(y^2)^4}\implies \begin{array}{llll} \pm5x^3y^2\\\\ 5|x^3|y^2\\\\ |5x^3y^2| \end{array}

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