Let the number of chickens = c.
Let the number of pigs = p.
A chicken has 1 head and 2 legs.
c number of chickens have c heads and 2c legs.
A pig has 1 head and 4 legs.
p number of pigs have p heads and 4p legs.
There are 40 heads.
Equation for heads:
c + p = 40
There are 110 legs.
Equation for legs:
2c + 4p = 110
System of equations:
c + p = 40
2c + 4p = 110
Solve the first equation of the system of equations for c:
c = 40 - p
Substitute 40 - p for c in the second equation:
2c + 4p = 110
2(40 - p) + 4p = 110
80 - 2p + 4p = 110
80 + 2p = 110
2p = 30
p = 15
Now substitute p = 15 in the first equation to find c.
c + p = 40
c + 15 = 40
c = 25
There are 25 chickens and 15 pigs.
Answer:
Step-by-step explanation:
Step-by-step explanation:
4t-2k+5k-t
=3t -3k
= 3( t-k)
2/3 cup of oatmeal - 10 granola bars
When the number of cups of oatmeal increases, the number of granola bars also increases.
If you use for example twice as many cups of oatmeal, you'll make twice as many granola bars.
Therefore, the first step is to calculate how many times 20 cups of oatmeal is more than 2/3 cup of oatmeal. To do it, divide 20 by 2/3.

You have 30 times as many cups of oatmeal, so you'll make 30 times as many granola bars.

300 granola bars can be made with 20 cups of oatmeal.