Find the equation Of a line that is parallel to the line X equals -10 and contains the point -9, 3

Please help 20 points and brainly how do u solve 7h= -(2h-18)

max2010maxim [7]

Answer:

h = 2

Step-by-step explanation:

7h = -(2h-18)

7h = -2h + 18

9h = 18

h = 18/9

h = 2

5 0

3 years ago

Find two consecutive integers such that one fifth of the first less one-ninth of the second is 3. Pls answer.

mart [117]

Answer:

35 and 36

Step-by-step explanation:

To solve this problem, we must interpret it line by line;

We are dealing with consecutive integers; these are integers with a difference of 1 between them.

let the first number = x

second number = x + 1

one - fifth of first;

$\frac{1}{5}$ x

one - ninth of the second;

$\frac{1}{9}$ (x + 1)

for the "less" ;

$\frac{1}{5}$ x - $\frac{1}{9}$ (x + 1) = 3

Multiply through by 45

45( $\frac{1}{5}$ x) - (45) $\frac{1}{9}$ (x + 1) = 3 x 45

9x - 5(x + 1) = 135

9x - 5x -5 = 135

4x = 135 + 5

4x = 140

x = 35

Now, x+1 = 35 + 1 = 36

The consecutive integers are 35 and 36

4 0

3 years ago

If Tanya starts at one vertex of the pentagon and walks

mario62 [17]

Answer:

Step-by-step explanation:

That will be the perimeter. Perimeter is the distance around. Add all five sides, be sure to put the unit behind.

I need more information to help any further.

8 0

3 years ago

What is the equation of a circle with a center located at (-3, 4) and a diameter of 14?

AnnZ [28]

Answer: (x + 3)^2 + (y - 4)^2 = 49

Step-by-step explanation:

The equation of a circle given the center and radius: (x - h)^2 + (y - k)^2 = r^2

Given: center (-3,4) ; h = -3 and k = 4

diameter = 14

To find the radius: divide the diameter by 2 = 14/2 = 7 = r

Center: (-3,4) and radius: 7

Equation of a circle: (x - h)^2 + (y - k) ^2 = r^2

Substitute h = -3, k = 4, r = 7

(x - (-3))^2 + (y - 4)^2 = 7^2

Answer:

Equation of the circle: (x + 3)^2 + (y - 4)^2 = 49

7 0

3 years ago

2 Here are two equations:

MatroZZZ [7]

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Step-by-step explanation:

a. Decide whether each neither of the equations,

i (3,4)

ii. (4,2.5)

ill. (5,5)

iv. (3,2)

To decide whether each point is solution to equations or not we will put the point in the equations

Equations are:

Equation 1: 6x + 4y = 34

Equation 2: 5x – 2y = 15

i (3,4)

Putting in Equation 1:

$6(3) + 4(4) = 34\\18+16=34\\34=34\\$

Putting in Equation 2:

$5(3) - 2(4) = 15\\15-8 = 15\\7\neq 15$

ii. (4,2.5)

Putting in Equation 1:

$6(4) + 4(2.5) = 34\\24+10=34\\34=34\\$

Putting in Equation 2:

$5(4) - 2(2.5) = 15\\20-5 = 15\\15=15$

ill. (5,5)

$6(5) + 4(5) = 34\\30+20=34\\50\neq 34$

Putting in Equation 2:

$5(5) - 2(5) = 15\\25-10 = 15\\15=15$

iv. (3,2)

$6(3) + 4(2) = 34\\18+8=34\\26\neq 34$

Putting in Equation 2:

$5(3) - 2(2) = 15\\15-4 = 15\\11\neq 15$

Hence,

(3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. Is it possible to have more than one (x, y) pair that is a solution to both

equations?

The simultaneous linear equations' solution is the point on which the lines intersect. Two lines can intersect only on one point. So a linear system cannot have more than one point as a solution

So,

a. (3,4) is only the solution to Equation 1.

(4, 2.5) is the solution to both equations

(5,5) is the solution to Equation 2

(3,2) is not the solution to any equation.

b. No, it is not possible to have more than one (x,y) pair that is solution to both equations

Keywords: Linear equations, Ordered pairs

Learn more about linear equations at:

#LearnwithBrainly

8 0

3 years ago