It's a cyclohexane ring with an ethyl group at 1 and a methyl group at 3. The Ethyl group is bigger and more important group get's the first position.
1-ethyl-3-methylcyclohexane
There are two naturally occurring isotopes of gallium: mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:
%Ga-71=100-60.11=39.89%
Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.
Thus, in this case:
Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)
From the periodic table, atomic mass of Ga is 69.723 amu.
Putting the values,

Thus,

Rearranging,

Therefore, mass of Ga-71 isotope is 70.9246 amu.
Answer:
The correct answer is reduction.
Explanation:
Nitrogen gas reacts with hydrogen gas and get reduced to form ammonia. In this reaction.This is important reaction of atmospheric nitrogen fixation.The reaction is carried out by many nitrogen fixing bacteria such as Azotobacter,Clostridium etc.
N2+3H2+6e- = 2NH3
Here is a universal law to balance chemical equations :
All chemical equations must be balanced
because of the law of conservation of mass.
It states that "matter
cannot be created or destroyed."
So, the number of atoms that you
start with at the beginning of the reaction must equal the number
of atoms that you end up with.
keeping this law in our mind,lets balance the<span> equation for the reaction of benzene and hydrogen to form cyclohexane.
</span><span>C 6 H 6 + H 2 → C 6 H 12.
Here is the balance chemical equation.
</span><span>2 C 6 H 6 + 6 H 2 → 2 C 6 H 12.</span>
this is a dilution question where a certain volume is taken from a more concentrated solution and diluted to make a solution with a lower concentration.
the dilution forumla is as follows
c1v1 = c2v2
where c1 is concentration and v1 is volume of the more concetrated solution
c2 is concentration and v2 is volume of the diluted solution
substituting the values in the equation
18.0 M x V = 0.126 M x 16.5 L
V = 0.1155 L
volume of 115.5 mL is taken from the 18.0 M solution and diluted upto 16.5 L solution.