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2 years ago

Which of the following options is correct?

Chemistry

1 answer:

Elena-2011 [213]2 years ago

8 0

Answer:

b. cellulose.

Explanation:

Cellulose is a polysaccharide consisting of a long chain of repeating glucose units (i.e., β-D-glucose units) that produce long unbranched chains. Cellulose can be considered as a natural polymer (i.e., a non-modified carbohydrate) because it is composed of repeated chains of β-D-glucose molecules stuck together. The cellulose polysaccharide is a principal component of plant cell walls.

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How many moles of oxygen are necessary to react completely with four moles of propane (CH)?

steposvetlana [31]

Answer:

20 mole of oxygen

Explanation:

1 mole of proprane reacts with 5 moles of oxygen so 4 time 5 equals 20

7 0

3 years ago

Se requieren preparar 1500 ml de una solución al 55% en masa de hidróxido de calcio, sabiendo que la densidad de dicha solución

Masja [62]

Respuesta:

968 g Ca(OH)₂

Explicación:

Paso 1: Calcular la masa de solución

Tenemos 1500 mL de una solución cuya densidad es 1.17 g/mL, es decir, 1 mL de solución tiene una masa de 1.17 g.

1500 mL × 1.17 g/mL = 1.76 × 10³ g

Paso 2: Calcular la masa de hidróxido de calcio en 1.76 × 10³ g de solución

La solución tiene una concentración de 55% en masa de hidróxido de calcio, es decir, cada 100 gramos de solución hay 55 gramos de hidróxido de calcio.

1.76 × 10³ g Solución × 55 g Ca(OH)₂/100 g Solución = 968 g Ca(OH)₂

6 0

2 years ago

Two equilibrium reactions of nitrogen with oxygen, with their corresponding equilibrium constants (Kc) at a certain temperature,

7nadin3 [17]

Answer:

Kc = 1.54e - 31 / 2.61e - 24

Explanation:

1 ) $N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$ ; Kc = 1.54e - 31

2) $N_{2}(gas) + 1/2O_{2}(gas)\rightarrow N_{2}O(gas)$ ; Kc = 2.16e - 24

upon reversing ( 2 ) equation

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$ Kc = 1/2.16e - 24

now adding 1 and reversed equation (2)

$N_{2}(gas) + O_{2}(gas)\rightarrow 2NO(gas)$

$N_{2}O(gas)\rightarrow N_{2}(gas) + 1/2O_{2}(gas)$

we get ,

$N_{2}O(gas) + 1/2O_{2}(gas)\rightarrow 2NO(gas)$ Kc = 1.54e-31 × 1/2.61e - 24

equilibrium constant of equation (3) is -

Kc = 1.54e - 31 / 2.61e - 24

3 0

2 years ago

Please help asap thank you.

Aleks [24]

Answer:

a)0.816g/l

b)0.241g/l

8 0

2 years ago

A sample of a compound made entirely from copper and oxygen was found to have a total mass of 0.143 g the mass of copper in the

tensa zangetsu [6.8K]

Mass of Oxygen: 0.0159 grams

Moles of Oxygen: 9.94x10^-4

To find the mass of oxygen, subtract the mass of copper from the total mass.

$0.143-0.1271=0.0159$

There are 0.0159 grams of Oxygen.

To find how many moles there are, divide the given amount of oxygen by the molar mass (atomic mass) of oxygen because that mass is the same as one mole of oxygen.

Molar mass of Oxygen: 16.00

$0.0159/16.00=9.94*10^{-4}$

There are 9.94*10^-4 moles of Oxygen.

6 0

10 months ago