<span>the limit as x approaches -3 of [g(x)-g(-3)]over(x+3) is the same as the derivative, or slope, of g(x) at the point x=-3, or g'(-3).
Since you are given the equation of the tangent line, the answer is just the slope of that line.
</span><span>2y+3=-(2/3)(x-3)
</span><span>6y+9=-2(x-3)
6y+9=-2x+6
6y=-2x-3
y= (-2x-3)/6
slope is -2/6 = </span>
Answer:
The answer is b = 8a
Step-by-step explanation:
As, 0 x 8 = 0
2 1/2 = 5/2, 5/2 x 8 = 20
5 x 8 = 40
7 1/2 = 15/2, 15/2 x 8 = 60
10 x 8 = 80
13 1/2 = 27/2, 27/2 x 8 = 108
So all variables "a" when multiplied by 8 will give us the value in "b"
So b = 8a
Answer:
4:7
Step-by-step explanation:
Okay, so first convert the feet to inches so 3x12=36. So the it's 36:63. Then if you simplify it you get 4:7.
A pyramid is regular if its base is a regular polygon, that is a polygon with equal sides and angle measures.
(and the lateral edges of the pyramid are also equal to each other)
Thus a regular rectangular pyramid is a regular pyramid with a square base, of side length say
x.
The lateral faces are equilateral triangles of side length
x.
The lateral surface area is 72 cm^2, thus the area of one face is 72/4=36/2=18 cm^2.
now we need to find
x. Consider the picture attached, showing one lateral face of the pyramid.
by the Pythagorean theorem:
thus,
thus:
(cm^2)
but
is exactly the base area, since the base is a square of sidelength =
x cm.
So, the total surface area = base area + lateral area =
cm^2
Answer:
cm^2
