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Colt1911 [192]
3 years ago
6

Max was on vacation twice as long as Jared and half as longas Wesley. The boys were on vacation a total of 3 weeks. How many day

s was each boy on vacation?
Mathematics
1 answer:
lord [1]3 years ago
4 0
Make an equation.
Also, convert 3 weeks into days ⇒ 3 · 7 = 21 days.

x + 2x + 4x = 21

x is Jared.
2x is Max (because half of 4 is 2).
4x is Wesley.

Now solve the equation.

7x = 21
x = 3

Jared = x
Max = 2x
Wesley = 4x

Jared = 3 days
Max = 2(3) = 6 days
Wesley = 4(3) = 12 days
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A new car is purchased for 15500 dollars. The value of the car depreciates at 6.5% per year. What will the value of the car be,
Aleksandr [31]

Answer:

$10356,22

Step-by-step explanation:

15500*(1-(6,5/100))^6=10356,22

3 0
3 years ago
What’s the product of....<br><br> (0.25)•(1.4)=
wolverine [178]

Answer:

0.35

Step-by-step explanation:

0.25 × 1.4 =

0.25×100=25

1.4 × 10 = 14

25×10=250

25×4=100

250+100=350

25×14=350

350÷1000(0.25》25, 1.4》14)

0.35

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3 years ago
I have found the area but I'm not sure how to find the perimeter.
Lana71 [14]

Answer:

20+20+24+24=88

88/2=44

88+44=132

Step-by-step explanation:

If you split it so there is a rectangle and a triangle, you find the perimeter of the rectangle then divide it in half.

6 0
3 years ago
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

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So I have a illustration
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