Question

How many moles of koh are needed to neutralize 0.4 moles of hno3

Answer 1

Answer:

0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

Explanation:

The equation of the reaction is

KOH(aq) + HNO3(aq) ------> KNO3(aq) + H2O(l)

This is a neutralization reaction. A neutralization reaction is a reaction between an acid and a base to form salt and water only.

Having written the balanced chemical reaction equation, we can now solve the prob!em stoichiometrically.

From the balanced reaction equation;

1 mole of KOH is required to neutralize 1 mole of HNO3

Therefore x moles of KOH is required to neutralize 0.4 moles of HNO3

x= 1×0.4/1 = 0.4 moles

Therefore, 0.4 moles of KOH is required to neutralize 0.4 moles of HNO3.

Answer 2

Answer:

0.4 moles of KOH

Explanation:

Hello,

In this case, due to the chemical reaction:

$KOH+HNO_3\rightarrow KNO_3+H_2O$

Since 0.4 moles of nitric acid are reacting, and it is in a 1:1 molar ratio with potassium hydroxide, also 0.4 moles of KOH will be needed to neutralize the 0.4 moles of nitric acid.

Best regards.