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koban [17]
2 years ago
14

What mass (in g) of potassium chlorate is decomposed if the yield of oxygen gas for the first reaction is 88.6%, if it is known

that all produced oxygen was used to make 23.6 g of carbon dioxide and the yield of the second reaction is 77.8%. Methane (CH4) is in excess. Enter a number in g to 1 decimal place. 2 KClO3 ⟶ 2KCl + 3O2 88.6% CH4 + 2O2 ⟶ CO2 + 2H2O 77.8%
Chemistry
1 answer:
Ainat [17]2 years ago
7 0

Using the stoichiometry and the number of moles involved in the reaction, The mass of KClO3 decomposed is 63.73 g.

Let us take it up from the second reaction;

Using stoichiometry , the equation of the reaction is;

CH4 + 2O2 ⟶ CO2 + 2H2O

Number of moles of CO2 produced = mass/molar mass

Actual yield of CO2 = 23.6 * 100/77.8 = 30.33 g

Number of moles in 30.33 g of CO2 = 30.33 g/44 g/mol = 0.69 moles

From the reaction equation;

2 moles of O2 yields 1 mole of CO2

x moles of O2 yields 0.69 moles of CO2

x = 2 *  0.69 /1

x = 1.38 moles of O2.

Mass of O2 used =  1.38 moles * 32 g/mol = 44.16 g

This becomes the actual yield of the first reaction.

Theoretical yield of oxygen = 44.16 g * 100/88.6

= 49.84 g of O2

Number of moles of O2 = 49.84 g/32 g/mol = 1.56 moles

Given the reaction equation;

KClO3 ⟶ 2KCl + 3O2

1 mole of KClO3 yields 3 moles of O2

x moles of O2 yields 1.56 moles of O2

x =  1 * 1.56/3

= 0.52 moles of KClO3

Mass of KClO3 decomposed = 0.52 moles * 122.55 g/mol = 63.73 g of KClO3

Learn more: brainly.com/question/9743981

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A car's fuel efficiency is 39.0 miles per gallon. What is its fuel efficiency in kilometers per liter? (1.6094 km=1 mile)(1 gall
MrRa [10]

Answer:

the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

Explanation:

The computation of the full efficiency in kilometers per liter is shown below:

39.0 miles ÷ gallon = (39.0 miles ÷ gallon) × (1.6094 km ÷ 1 miles)  × (1 gallon ÷ 3.79 L)

Now cut the opposite miles and gallons

So, the fuel efficiency would be

= 16.561 kilometers per liter

Hence, the fuel efficiency in kilometers per liter is 16.561 kilometer per liter

5 0
2 years ago
A 25.0 g sample of an alloy was heated to 100.0 oC and dropped into a beaker containing 90 grams of water at 25.32 oC. The tempe
kaheart [24]

Answer:

The specific heat of the alloy C_{a} = 0.37 \frac{KJ}{Kg K}

Explanation:

Mass of an alloy m_{a} = 25 gm

Initial temperature T_{a} = 100°c = 373 K

Mass of water m_{w} = 90 gm

Initial temperature of water T_{w} = 25.32 °c = 298.32 K

Final temperature T_{f} = 27.18 °c = 300.18 K

From energy balance equation

Heat lost by alloy = Heat gain by water

m_{a} C_{a}  [T_{a} - T_{f}] = m_{w} C_w (T_{f} -T_{w} )

25 × C_{a} × ( 373 - 300.18 ) = 90 × 4.2 (300.18 - 298.32)

C_{a} = 0.37 \frac{KJ}{Kg K}

This is the specific heat of the alloy.

6 0
3 years ago
Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A
BabaBlast [244]

<u>Answer:</u>

<u>For A:</u> The energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

<u>For B:</u> The energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

<u>For C:</u> The energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

<u>Explanation:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

E=n\rimes N_A\times \frac{hc}{\lambda}        ......(1)

where,

h = Planck's constant  = 6.62\times 10^{-34}Js

E = energy of the light

c = speed of light = 3\times 10^8m/s

\lambda = wavelength of light

N_A = Avogadro's number = 6.022\times 10^{23}

n = number of moles of photons = 1.70 moles

Conversion factor used:  1m=10^9nm

  • <u>For A:</u>

Wavelength of infrared radiation = 1600nm=1.6\times 10^6m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 1.271\times 10^5J

  • <u>For B:</u>

Wavelength of visible light = 505nm=5.05\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J

Hence, the energy of the given amount of photons for infrared radiation is 4.026\times 10^5J

  • <u>For C:</u>

Wavelength of ultraviolet radiation = 150nm=1.5\times 10^7m

Putting values in equation 1, we get:

E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J

Hence, the energy of the given amount of photons for infrared radiation is 1.355\times 10^6J

3 0
3 years ago
The pH of a strong base is 12.2 at 25 degrees. what is its hydroxide-ion concentration?
marta [7]

Answer:

[OH⁻] = 0.016

Explanation:

Given data:

pH = 12.2

Hydroxide ion concentration = ?

Solution:

It is known that,

pH + pOH = 14

12.2 + pOH = 14

pOH = 14 - 12.2

pOH = 1.8

pOH = -log [OH⁻]

1.8 = -log [OH⁻]

10⁻¹°⁸ = [OH⁻]

[OH⁻] = 0.016

3 0
3 years ago
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