Answer:
neither
geometric progression
arithmetic progression
Step-by-step explanation:
Given:
sequences: 


To find: which of the given sequence forms arithmetic progression, geometric progression or neither of them
Solution:
A sequence forms an arithmetic progression if difference between terms remain same.
A sequence forms a geometric progression if ratio of the consecutive terms is same.
For
:

Hence,the given sequence does not form an arithmetic progression.

Hence,the given sequence does not form a geometric progression.
So,
is neither an arithmetic progression nor a geometric progression.
For
:

As ratio of the consecutive terms is same, the sequence forms a geometric progression.
For
:

As the difference between the consecutive terms is the same, the sequence forms an arithmetic progression.
Answer:
78%
Convert fraction (ratio) 39 / 50 Answer: 78%
34% diesel 29% total crude oil -60 million barrels Total.
Answer:
60.39 inches
Step-by-step explanation:
Given that:
A Pac-Man poster which is having three fourth of a circle and there are two sides.
Diameter of circle = 18 inches
Sides of Pac-Man poster = 9 inches
To find:
Perimeter of the Pac-Man poster.
Solution:
Perimeter of a figure is nothing but equal to the periphery i.e. the outer area of the circle/figure.
Perimeter of a circle is given by the formula:
Perimeter = 
is the radius of the circle.
Radius is half of perimeter.

Perimeter of the Pac-Man poster = Perimeter of
circle + 2 sides
Perimeter of the Pac-Man poster =
+ 9+9 = 42.39+28 = <em>60.39 inches</em>
Answer:
Step-by-step explanation:
Since the box contains a cylinder, the height of the box must be gt; = cylinder height
And the area at the bottom of the box is definitely larger than the area at the bottom of the cylinder.
The area at the bottom of the cylinder is PI r squared,
If the bottom of the box is a square, then the area of the bottom is 4r^2, whereas the bottom tends to be polygon, which is equivalent to cutting the circle into equal parts by circle cutting.
So the area at the bottom of the box is
,
It follows that the volume of the box is greater than the volume of the cylinder