X can be any real number
As long as it is to the power of 0, it will equal one. And because 6^0 = 1, 1^x can be any positive number, and it will still give you one.
As stated by WojtekR, even negative numbers can get 1
x = - 5
(6^0)^-5 = 1^-5 = 1/1 = 1
~ Thanks @WojtekR
Answer:
(2,-5) and (2,1).
Step-by-step explanation:
We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.
A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.
Standard form of a circle is

where, (h,k) is center and r is the radius.


Now, put x=2.




Taking square root on both sides.




So, the y-coordinates of the points are -5 and 1.
Therefore, the required points are (2,-5) and (2,1).
Answer:31 dived by 81 is 0.3703
Step-by-step explanation:
Answer:
(b) (x -10)(x +10)
Step-by-step explanation:
The factorization of the difference of squares is a special form:
a² -b² = (a -b)(a +b)
<h3>Application</h3>
Your expression is recognizable as the difference of squares:
x² -100 = x -10²
Using the above form, the factorization is ...
= (x -10)(x +10) . . . . . . . . matches the second choice
Answer:
D. 1
Step-by-step explanation:
We have the expression, 
We get, eliminating the cosecant function,

As, sinx is reciprocal of cosecx and cosx is reciprocal of secx,
i.e. 
i.e. 
Since, we know that, 
Thus,

So, after simplifying, we get that the result is 1.
Hence, option D is correct.