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sergij07 [2.7K]
3 years ago
9

A student caries out an experiment and dissolves 10.0 g of sodium bromide. NaBr, in 200g of water. What is the molality of the s

olution?
Chemistry
1 answer:
Pavel [41]3 years ago
4 0

Answer:

0.485mol/kg

Explanation:

Molality is defined as the ratio of the number of moles of a solute to the kilogram of a solvent which is usually water.

Mass of NaBr = 10g

Molar mass of NaBr= 23+80=103g/mol

Mole of NaBr = mass / molar mass=10g/103g/mol= 0.097mol

Molality= Mole of a solute/ mass of solvent in kg

Mole of a solute( NaBr)= 0.097mol; mass of solvent( water in kg)= 200g. To convert to kg: 200g/1000g= 0.2kg

Molality = 0.097mol/0.2kg = 0.485mol/kg

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