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dybincka [34]
4 years ago
10

What are organelles? NEED ASAP!!! HELP!!

Chemistry
2 answers:
Brrunno [24]4 years ago
4 0

Answer:

Explanation:

organelle is a specialized subunit within a cell that has a specific function. for example endoplasmic reticulum, golgi apparauts, vacuols, etc.

Maslowich4 years ago
3 0

Answer:

any of a number of organized or specialized structures within a living cell.

Explanation:

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What is the value of k, at 25 degrees Celsius
Dimas [21]
<h3>Answer:</h3>

298.15 K

<h3>Explanation:</h3>

W e are supposed to calculate the Value of K at 25°C

Assuming the value of K represent K, the question wants us to convert  degree Celsius to Kelvin.

  • To convert degrees Celsius to kelvin scale, we use the relationship;
  • Kelvin (K) = Degrees Celsius + 273.15 ; 273.5 is a constant
  • That is, to convert temperature from °C to Kelvin we add a constant of 273.15 to the °C given.

In this case;

Temperature is 273.15 °c

Thus, to Kelvin scale temperature will be;

= 25°C + 273.15

= 298.15 K

Therefore, the value of K, at 25°C is 298.15 K

7 0
3 years ago
Which of the following is an example that includes evidence of a chemical reaction?
Elenna [48]
It is c took the test
6 0
3 years ago
What makes matelloids a group of there own
11111nata11111 [884]
They have thier own group because because they have traits or metals and nonmetals
7 0
3 years ago
What is the hybridization and shape for an XeF6 2+ molecule?
Anna11 [10]

Answer:

Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²

Explanation:

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²

Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48

Ca. #Substrate e⁻ = 6F = 6(8) = 48

#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs

#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs

BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²    

XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)      

8 0
3 years ago
When energy is added to a substance at constant volume and pressure, its temperature increases except ________.
Travka [436]

A. When the substance is in its gaseous state.

<u>Explanation:</u>

When a substance is expanding against its constant volume and pressure, its temperature increases except when the substance is in gaseous state and not in liquid or solid state. So the internal energy increase in the system not only increases and maintaining the volume and pressure of the system remains constant in its gaseous phase. In the first law of Thermodynamics, it is used specifically that to especially in the case of gaseous system.  

<u></u>

7 0
3 years ago
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