**Answer : The enthalpy of reaction is, 67.716 KJ/mole**

**Explanation :**

**First we have to calculate the moles of and .**

**Now we have to calculate the moles of AgCl formed.**

The balanced chemical reaction will be,

As, 1 mole of react with 1 mole of to give 1 mole of

So, 0.005 mole of react with 0.005 mole of to give 1 mole of

The moles of AgCl formed = 0.005 mole

Total volume of the solution = 50.0 ml + 50.0 ml = 100.0 ml

**Now we have to calculate the mass of solution.**

Mass of the solution = Density of the solution × Volume of the solution

Mass of the solution = 1.00 g/ml × 100.0 ml = 100 g

**Now we have to calculate the heat.**

where,

q = heat

C = specific heat capacity =

m = mass = 100 g

= final temperature =

= initial temperature =

Now put all the given values in the above expression, we get:

**Now we have to calculate the enthalpy of the reaction.**

where,

= enthalpy of reaction = ?

q = heat of reaction = 338.58 J

n = moles of reaction = 0.005 mole

Now put all the given values in above expression, we get:

**Conversion used : (1 KJ = 1000 J)**

**Therefore, the enthalpy of reaction is, 67.716 KJ/mole**