<h3>
Answer: 21600 </h3>
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Explanation:
There are 6 letters to pick from {A,B,C,D,E,F} and we have two slots to fill, where no repeats are allowed. This means we have 6*5 = 30 different ways to pick two letters.
There are 10 digits to pick from {0,1,2,...,9} and there are 3 slots to fill. This gives 10*9*8 = 720 different permutations for this portion.
Overall, we have 30*720 = 21600 different serial numbers possible.
It is either 0.80 or 80% I believe
Answer: 7.5
Form your proportion. Let x be the width of QRST.
Length of ABCD Length of QRST
----------------------- = -------------------------
Width of ABCD Width of QRST
8/5 = 12/x
Solve for x by cross-multiplying.
(8)(x) = (12)(5)
8x = 60
x = 7.5
there is no B i see A and -5A unless its for -5A??
84/4=21
now take the 2 even numbers below 21 and the 2 even numbers above 21
18 +20 + 22 +24 = 84
the numbers are 18, 20, 22 & 24