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Ganezh [65]
3 years ago
14

Any two differences between SI units and derived unitshelp me...​

Physics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

SI unit

1) SI unit does not depend on other.

2) they have their own identity.

Derived unit

1) They depend upon other or fundamental unit.

2) they don't have their own identity.

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choose the correct anwer 9: the range of the gravitional force is given by A: 10_2m B:10_15m C: infinite D: 10_10m​
frosja888 [35]

Answer:

The answer is C

Explanation:

The magnitude of the gravitational force depends inversely on the square of the radial distance between the centers of the two masses. Thus, essentially, the force can only fall to zero, when the denominator that is r becomes infinite.

6 0
3 years ago
When a person steps forward out of a small boat onto a dock, the boat recoils backward in the water. why does this occur??
bixtya [17]
Here is the correct answer of the given question above. When a person steps forward out of a small boat onto a dock, the boat recoils backward in the water and this occurs because the total momentum of the system is conserved. Hope this helps.
4 0
3 years ago
Read 2 more answers
Question 2 (1 point)
Tju [1.3M]

Answer:

I know someone anwsered but it would be 400M

Explanation:

i initial velocity (u)=10m/s

acceleration (a)=0

time taken (t) =40s

then distance (s)=u t +1/2 a t^2

s= u t +0 (as a is 0)

s= 10 x 40

s= 400M

7 0
3 years ago
NEED HELP FAST!<br> select drop box.<br> questions and options are in pictures.
cluponka [151]

Answer:

First is incrcersing mangnetic field second photosphere

Explanation:

sorry if the first one is wrong

8 0
3 years ago
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A wet bar of soap slides down a ramp 9.2 m long inclined at 8.0∘ .
xenn [34]

Answer:

The time taken by the bar to reach the bottom t=4.886s

Given:

Displacement of the bar S=9.2m

Angle of inclination \theta=8.0^{\circ}

Coefficient of friction factor \mu k=0.056

To find:

How long it takes to reach the bottom ‘t’

<u>Step by Step Explanation:</u>

Solution:

We know that the formula for weight of the soap bar is given as

F_{g}=m g \sin \theta

The frictional force acting on this soap bar is determined by

F_{f}=\mu m g \cos \theta

To determine the constant acceleration of the bar, we derive as

F=m a

Here F=F_{g}-F_{f} and thus

F_{g}-F_{f}=m am g \sin \theta-\mu m g \cos \theta=m a

a=g \sin \theta-\mu g \cos \theta

WhereF_{g}=Force imparted due to weight

F_{f}=Frictional Force

m=Mass of the bar

g=Acceleration due to gravity

a=Acceleration of the bar

\sin \theta and \cos \theta are the angles involved in the system

If the bar starts from the rest

Equations of motion involved in calculating the displacement of the bar is given as

s=\frac{1}{2} a t^{2}, From this

 a t^{2}=2 s

t^{2}=\frac{2 s}{a}

t=\sqrt{\frac{2 s}{a}}

Where s= displacement or length moved by the bar

a=Acceleration of the bar

t=Time taken to reach bottom

Substitute all the known values in the above equation we get

t=\sqrt{\frac{2 \times 9.2}{a}} and we know that

a=g \sin \theta-\mu g \cos \theta

=9.8 \times \sin 8.0-0.056 \times 9.8 \times \cos 8.0

=1.364-0.543

a=0.821

t=\sqrt{\frac{2 \times 9.2}{0.821}}

t=\sqrt{\frac{19.6}{0.821}}

t=\sqrt{23.87332}

t=4.886s

Result:

Thus the time taken by the bar to reach the bottom is t=4.886s

3 0
3 years ago
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