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lina2011 [118]
3 years ago
7

Based on Planet Z's size, orbital distance, and rotation rate, which of the following properties is it likely to have?

Physics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

Planet Z will have the following properties;

Active Volcanoes

Active Tectonics

An Atmosphere produced by outgassing

Explanation:

The little terrestrial worlds have heat shorter than the much bigger terrestrial worlds, so the bigger worlds tend to have active volcanism and tectonics. These active volcanism and tectonics are likely to erase ancient craters. The active volcanism and tectonics would create an atmosphere by producing gases.

It is know that the Terrestrial worlds that are not far from the star have higher surface temperature.

Fast rate of rotation can cause winds and strong storms but here it is slower compared to earth. Also, a tilt of axis causes seasons.

The properties the star have are active volcanoes, active tectonics and an atmosphere produced by outgassing.

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Feliz [49]
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J

8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m

9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333


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3 years ago
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WILL UPVOTE EVERY ANSWER! MULTIPLE CHOICE QUESTION!
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What horizontally-applied force will accelerate a crate of mass 400 kg at 1 meter per second per second across a factory floor a
son4ous [18]

Answer:

The horizontally applied force = 2360 N

Explanation:

<em>Force:</em> Force can be defined as the product of mass and acceleration. the S.I unit of force is Newton (N)

Fh = Fr + ma......... Equation 1

Where Fh = horizontally applied force, Fr = friction force, m = mass of the crate, a = acceleration of the crate.

<em>Given: m = 400 kg, a = 1 m/s²</em>

Fr = 1/2 W, W = mg  ⇒W = 400×9.8 = 3920 N

∴Fr = 1/2(3920), Fr = 1960 N

Substituting these values into equation 1

Fh = 1960 + 400×1

Fh = 1960 + 400

Fh = 2360 N

Therefore the horizontally applied force = 2360 N

6 0
3 years ago
Ms. Stafford wants to try racing with a push start. A student pushes her at 5 m/s before the rocket kicks in. The rocket still o
Gnom [1K]
The initial velocity of Ms. Stafford is v_0 = 5 m/s, while her acceleration is 
a=4 m/s^2
This is a uniform accelerated motion, so we can calculate the total distance travelled by Ms. Stafford in a time of t=7.0 s using the law of motion for a uniform accelerated motion:
S=v_0t +  \frac{1}{2} at^2 = (5 m/s)(7.0 s)+ \frac{1}{2}(2 m/s^2)(7.0 s)^2 = 84 m
8 0
3 years ago
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