Answer:
Explanation:
m = ρV = 1.03( 1000 kg/m³)(π(2² m²)(3.0 m)) = 12360π kg
m ≈ 38,830 kg
Force on the particle is defined as the application of the force field of one particle on another particle. The magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
<h3>What is electrical force?</h3>
Force on the particle is defined as the application of the force field of one particle on another particle. It is a type of virtual force.
The given data in the problem is
q₁ is the negative charge = 6 µC=6×10⁻⁶ C
q₂ is the positive charge = 3 µC=3×10⁻⁶ C
r is the distance between the charges=0.002 m
is the electric force =?
The value of electric force will be;

Hence the magnitude and direction of the electrical force will be 4.05×10⁴N towards the north.
To learn more about the electrical force refer to the link;
brainly.com/question/1076352
Answer:
sound wave-electrical wave-radio wave
Answer:
The total work done by the mover is 2.81 kJ.
Explanation:
Given the 46 kg crate is displaced by 10.4 meters.
And the acceleration is zero. Also, 
let
is applied force,
is the net force,
is the mass and 
and 

As the acceleration is zero, the net force will also be zero.
.

Now, we know the work done is force times displacement.
So,

So, the total work done by the mover to displace 46 kg crate by 10.4 meters 2.81 kJ.