Question

URGENT!!

Answer 1

Answer:

A. 14.7 cm

Step-by-step explanation:

To find the measure of side a, we will simply use the sine formula

$\frac{sin A}{a}$   =  $\frac{sin B}{b}$

where A,B are angles and   a,b  are sides of the triangle

from the question given, angle A = 60°        angle B = 45°     b = 12cm      a = ?

$\frac{sin 60}{a}$  =  $\frac{sin 45}{12}$

cross-multiply

a sin45 = 12 sin60

Divide both-side by sin 45

a = 12 sin 60/ sin45

a ≈ 14.7  cm

Answer 2

Answer:

A. 14.7cm

Step-by-step explanation:

In Triangle ABC

$\angle A=60^\circ\\\angle B=45^\circ\\b=12cm$

We are to determine the measure of side a.

Using Law of Sines

$\dfrac{a}{\sin A}= \dfrac{b}{\sin B}\\\dfrac{a}{\sin 60^\circ}= \dfrac{12}{\sin 45^\circ}\\\\ Cross multiply\\a*sin 45^\circ=12*\sin 60^\circ\\ Divide both sides by sin 45^\circ\\\dfrac{a*sin 45^\circ}{sin 45^\circ}= \dfrac{12*\sin 60^\circ}{\sin 45^\circ}\\\\a=14.7 cm (to the nearest tenth of a cm)$

The correct option is A.