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3 years ago

A parabola intersects the x-axis at x=3 and x=9 . What is the axis of symmetry?

Mathematics

1 answer:

fomenos3 years ago

4 0

Answer:

The x-coordinate of the parabola's vertex is 6.

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How long have the nashville predators been a team?

olganol [36]

This is the Internet. It's really easy to look up.

3 0

4 years ago

You need 200 mL of a 10% alcohol solution. On hand, you have a 25% alcohol mixture. How much of the 25%

Anastasy [175]

so yull do math I'm guna do different number just plug these in for.your numbers 225/(375+x)=25

cross multiply land solve900-375 x=525 then cheak

225/(375+525) = .25

4 0

3 years ago

Andrew had $50 and saved x dollars in a month. Anne had $60 and saved half as many dollars in a month as Andrew. How many did An

Amanda [17]

Answer:

$20

Step-by-step explanation:

Set up an equation where x is the number of dollars Andrew saved in a month:

50 + x = 60 + 0.5x

Solve for x:

50 + 0.5x = 60

0.5x = 10

x = 20

So, Andrew saved $20

6 0

3 years ago

Read 2 more answers

Someone please answer this!!

OleMash [197]

Here's the solution,

The given triangle is a Right angled triangle,

So, by applying Pythagoras theorem:

=》

${c}^{2} = {4}^{2} + 3 {}^{2}$

=》

${c}^{2} = 16 + 9$

=》

${c}^{2} = 25$

=》

$c = \sqrt{25}$

=》

$c = 5$

value of c = 5 miles

6 0

3 years ago

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After painting his porch jamil has 1/4 of a can of paint remaining the can has a radius of 8cm and a height of 20cm he wants to

ozzi

Answer:

12.8 cm

Step-by-step explanation:

Radius of the can is 8 cm and height is 20 cm.

It is given that after painting his porch Jamil has $\frac{1}{4}$ of a can of paint remaining. So, first we need to find the total amount of paint in the can.

Total amount of paint in the can is $\text{Base area}\times\text{height}$

So, paint in the can $=\pi r^{2}\times h$

$=\pi (8)^{2}\times 20$

Now $\frac{1}{4}$ of the can is $\frac{1}{4}\times \pi (8)^{2}\times 20$

$=320\pi$ cubic cm.

Now, let the height of the smaller can be h cm.

Radius of the smaller can is 5 cm.

As, the paint is poured into the smaller can the volume of both the cans will be same.

$\pi (5)^{2}\times h=320\pi$

$h=\frac{320\pi}{25\pi}$

$h=12.8$

Hence, height of the smaller can to hold the paint must be 12.8 cm.

5 0

3 years ago

Read 2 more answers