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4 years ago

Solve for V: V/9+-5 = 2

Mathematics

1 answer:

Vesna [10]4 years ago

6 0

V=63

V-45=18

V=18+45

V= 63

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Solve the equation 425x=850

mylen [45]

Answer:2

Step-by-step explanation:

DIVIDE 425 ON BOTH SIDES

AND U WILL GET 2

7 0

4 years ago

angel's dad bought a television for her completing all of her digital learning day lesson. he want to warp the gift. the box mea

atroni [7]

Answer: 13 sheets of paper

Step-by-step explanation:

We are given the dimensions of the box and the wrap paper:

Box:

$(56 in)(8 in)(36 in)$

Warp paper:

$(26 in)(17 in)$

Now we need to find the surface area of the box and the area of the wrap paper:

Box:

$surface_{1}=(56 in)(8 in)(2)=896 in^{2}$

$surface_{2}=(8 in)(36 in)(2)=576 in^{2}$

$surface_{3}=(56 in)(36 in)(2)=4032 in^{2}$

$surface-area=896 in^{2}+576 in^{2}+4032 in^{2}=5504 in^{2}$

Warp paper:

$area=(26 in)(17 in)=442 in^{2}$

Dividing the area of the box by the area of the paper:

$\frac{surface-area}{area}=\frac{5504 in^{2}}{442 in^{2}}=12.45 \approx 13$

This means Angel's dad needs to purchase 13 sheets of wrapping paper.

4 0

4 years ago

What is the product?

ad-work [718]

Answer is C, just multiply and expand.

7 0

4 years ago

Read 2 more answers

I have no idea how to or how I would even start to write a problem like this, Please help.

TEA [102]

That's an easy one! The year would be Monday Janurary 27th, 3000 and it would be the year of the monkey!

8 0

3 years ago

Brook makes this conjecture: Because the angles are equal, the proportion of area of each sector relative to the area of the giv

AnnZ [28]

Answer:

The Brooks conjecture is true as the proportion of the area of a sector to the area of a circle is only dependent on the angle.

Step-by-step explanation:

The area of a sector for a radius r and an angle θ is given as

$\Delta Sector=\dfrac{1}{2}r^2\theta$

Whereas the area of a circle for a radius r is given as

$\Delta Circle=\pi r^2$

Now the ratio is given as

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\dfrac{1}{2}r^2\theta}{\pi r^2}$

Here as r is the radius of the circle and it is the same therefore the above ratio is simplified to

$\dfrac{\Delta Sector}{\Delta Circle}=\dfrac{\theta}{2\pi }$

Here as π is constant the only variable here is θ. Thus according to Brooks conjecture when the angles are equal, the proportion of area of each sector relative to the area of the given circle is also equal is true.

6 0

3 years ago