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mart [117]
3 years ago
15

What is the distance between the two points? 20 40 45 58

Mathematics
2 answers:
MArishka [77]3 years ago
8 0

Answer:

your question Is not in Mark

SSSSS [86.1K]3 years ago
7 0
What is the question
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A rectangle is 3 1/3 ft long and 2 1/3 feet wide. What is the distance around the rectangle?
Sonja [21]
3 1/3= 10/3
2 1/3= 7/3
7/3 + 10/3= 17/3
17/3 (2)+ 34/3
34/3= 11 1/3
final answer = 11 1/3
8 0
3 years ago
Read 2 more answers
PLEASE HELP I AM HOPLESS ON THIS
ValentinkaMS [17]

Answer: (-2,1)

Step-by-step explanation:

Read it lije (x,y)

8 0
2 years ago
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Geometry// question #8
MAVERICK [17]

Answer:

see explanation

Step-by-step explanation:

The translation rule

(x, y ) → (x + 3, y - 2 )

Means add 3 to the original x- coordinate and subtract 2 from the original y- coordinate, thus

A(- 4, 1 ) → A'(- 4 + 3, 1 - 2 ) → A'(- 1, - 1 )

B(1, 1 ) → B'(1 + 3, 1 - 2 ) → B'(4, - 1 )

C(1, - 2 ) → C'(1 + 3, - 2 - 2 ) → C'(4, - 4 )

D(- 4, - 2 ) → D'(- 4 + 3, - 2 - 2 ) → D'(- 1, - 4 )

4 0
3 years ago
If you answer God will bless you:
VashaNatasha [74]

Answer:

600 m³

Step-by-step explanation:

Given:

  • length of swimming pool = 30 m
  • width of swimming pool = 10 m
  • depth at deep end = 3 m
  • depth at shallow end = 1 m

To find the volume of the water in the pool, find the area of a cross section (see attached image) and multiply it by the width of the pool.

<u>Area of cross section</u>

= area of rectangle - area of triangle

= (3 × 30) - [1/2 × 30 × (3 - 1)]

= 90 - 30

= 60 m²

<u>Volume of pool</u>

= area of cross section × width

= 60 × 10

= 600 m³

6 0
2 years ago
A number is multiplied by 16, and that product is added to 8. The sum is equal to the product of 4 and 10. Find the number.
Ymorist [56]

Your sum is 4 times 10, or 40. We want to end up with 40. Subtract 8 because you added 8 before to work backwards. You get 32. Divide by 16 because the opposite of multiplication is division. You would get 2.

5 0
3 years ago
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