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Troyanec [42]
2 years ago
10

Which equation in rectangular form describes the parametric equations x=5-3cost and y=4+2sint?

Mathematics
1 answer:
Sidana [21]2 years ago
8 0

Answer:

D. (-x+5)^2/9+(y-4)^2/4=1    (I assume there was a mistype)

Step-by-step explanation:

The first step is isolating the sine and cosine functions.

x=5-3cos(t)

x + 3cos(t) = 5

3cos(t) = 5 - x

cos(t) = (5 - x)/3

y=4+2sin(t)

y - 4 = 2sin(t)

(y - 4)/2 = sin(t)

Then, square at both sides of the equal sign

cos²(t) = (5 - x)²/3² = (5 - x)²/9

sin²(t) = (y - 4)²/2² = (y - 4)²/4

Recall the trigonometric identity and replace.

cos²(t) + sin²(t) = 1

(5 - x)²/9 + (y - 4)²/4 = 1

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Find the slope of the line(s) passing through the given points. Then tell whether the line(s) rises, falls, is horizontal, or is
bonufazy [111]

Answer:

21) falls

22) vertical

23) rises

24) rises

25) falls

26) horizontal

27) rises

28) horizontal

29) falls

Step-by-step explanation:

We shall use the slope formula m=\frac{y_2-y_1}{x_2-x_1} to calculate the slopes of the line passing through each pair of point.

21: (3,1), (2,6)

The slope is m=\frac{6-1}{2-3}

\implies m=\frac{5}{-1}=-5.

A negative slope means this line falls

22) (-2,5), (-2,4)

The slope is m=\frac{4-5}{-2- -2}=\frac{-1}{0}= undefined

An undefined slope means this line is vertical

23) The given point is (0,8) (2,10)

The slope is m=\frac{10-8}{2-0}=\frac{2}{2}=+1

A positive slope means this line rises

24)  The points are (-3,-3), (3,1)

The slope is m=\frac{1--3}{3--3}=\frac{4}{6}=+\frac{2}{3}

A positive slope means this line rises

25) The points are: (5,0) (6,-2)

Slope: m=\frac{-2-0}{6-5}=\frac{-2}{1}=-2

A negative slope means this line falls

26)  The points are (-2,-8) , (5,-8).

Slope: m=\frac{-8--8}{5--2}=\frac{0}{7}=0

A zero slope means this line is horizontal

27) The points are: (-1,2) , (5,3)

Slope: m=\frac{3-2}{5--1}=+\frac{1}{6}

A positive slope means this line rises

28) The points are: (\frac{1}{2},4), (-1,4)

Slope: m=\frac{4-4}{-1-\frac{1}{2}}=\frac{0}{\frac{1}{2}}=0

A zero slope means the line is horizontal

29) The points are: (4,\frac{1}{2}), (5,\frac{1}{4})

Slope: m=\frac{\frac{1}{4}-\frac{1}{2}}{5-4}=-\frac{1}{4}

A negative slope means this line falls.

6 0
3 years ago
I NEED HELP PLEASE, THANKS! :) Determine the zeros for and the end behavior of f(x) = x(x – 4)(x + 2)^4.
Amiraneli [1.4K]

Answer:  a) zeros: x = {0, 4, -2}

               b) as x → ∞,  y → ∞

                   as x → -∞,  y → ∞

<u>Step-by-step explanation:</u>

I think you mean (a) find the zeros and (b) describe the end behavior

(a) Find the zeros by setting each factor equal to zero and solving for x:

      x (x - 4) (x + 2)⁴ = 0

  • x = 0   Multiplicity of 1  --> odd multiplicity so it crosses the x-axis
  • x = 4  Multiplicity of 1  --> odd multiplicity so it crosses the x-axis
  • x = -2 <u>Multiplicity of 4 </u> --> even multiplicity so it touches the x-axis

                       Degree  =  6

(b) End behavior is determined by the following two criteria:

  1. Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
  2. Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side

Sign of the leading coefficient is Positive so right side goes UP

                                                                        as x → ∞,  y → ∞

Degree of 6 is Even so Left side is the same direction as right (UP)

                                                                        as x → -∞,  y → ∞

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Answer:

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