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balu736 [363]
2 years ago
8

I need help pleaseee, I’ve been stuck on this for a while

Mathematics
1 answer:
mina [271]2 years ago
7 0

Step-by-step explanation:

The question asks for you to talk about precision and accuracy, precision is defined by how close the results are when repeated so the three results are precise. The difference in weight between the three measurements is within .3g of each other so this proves your precision is good.

However, the accuracy is bad because the results and the actual weight of the apple are far away, the mean distance can be calculated via adding up all three measurements and dividing by three:

167 + 166.9 + 167.2 = 501.1

501.1 ÷ 3 = 167.03

172 - 167.03 = 4.97

So the mean distance is 4.97g away from the actual weight of the apple, this shows that the results are not accurate.

Hope this helps!

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You saved $20,000.00 and want to diversify your monies. You invest 45% in a Treasury bond for 3 years at 4.35% APR compounded an
Maru [420]

Compound Interest

A total of $20,000 is invested in different assets.

45% is invested in a Treasury bond for 3 years at 4.35 APR compounded annually.

For this investment, the principal is P = 0.45*$20,000 = $9,000.

The compounding period is yearly, thus the interest rate is:

i = 4.35 / 100 = 0.0435

The duration (in periods) is n = 3

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M=P_{}(1+i)^n

Substituting:

\begin{gathered} M=\$9,000_{}(1+0.0435)^3 \\ M=\$9,000\cdot1.136259062875 \\ M=\$10,226.33 \end{gathered}

The second investment is a CD at 3.75% APR for 3 years compounded annually. The parameters for the calculations are as follows:

P = 15% of $20,000 = $3,000

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Calculating:

\begin{gathered} M=\$3,000_{}(1+0.0375)^3 \\ M=\$3,000\cdot1.116771484375 \\ M=\$3,350.31 \end{gathered}

The third investment is in a stock plan. The initial value of the investment is

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By the end of the first year, the stock plan increased by 8%, thus its value is:

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By the end of the second year, the stock plan decreased by 4$, thus the value is:

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Finally, the stock plan increases by 6%, resulting in a final balance of:

M3 = $4,608 * 1.06 = $4,884.48

Finally, the last investment is in a savings account at 2.90% APR compounded annually for 3 years (not mentioned, but assumed).

P = $20,000 - $9,000- $3,000 - $4,000 = $4,000

i = 2.90 / 100 = 0.029

n = 3

Calculating:

\begin{gathered} M=\$4,000_{}(1+0.029)^3 \\ M=\$4,000\cdot1.089547389 \\ M=\$4,358.19 \end{gathered}

To summarize, the final balances for each type of investment at the end of the third year are:

Investment 1; $10,226.33

Investment 2: $3,350.31

Investment 3: $4,884.48

Investment 4: $4,358.19

Total balance: $22,819.32

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