Approximately there are some of these on the we
First row all correct second rows all wrong and the first on of third row is correct be the last two are incorrect
Answer:
steps below
Step-by-step explanation:
3.2.1 AD = DB* sin 2 = DB * sin θ .. DE // AB ∠2= θ ... (1)
By laws of sines: DB / sin ∠5 = x / sin ∠4
∠4 = θ-α ∠5 = 180°-<u>∠1</u>-∠4 = 180°-<u>∠3</u>-∠4 = 180°-(90°-θ)-(θ-α)) = 90°+α
DB = (x*sin ∠5)/sin (θ-α)
= (x* sin (90°+α)) / sin (θ-α)
AD = DB*sinθ
= (x* sin (90°+α))*sinθ / sin (θ-α)
= x* (sin90°cosα+cos90°sinα)*sinθ / sin (θ-α) .... sin90°=1, cos90°=0
= x* cosα* sinθ / sin (θ-α)
3.2.2 Please apply Laws of sines to calculate the length
Answer:
a) -0.5 • 1.7 - 0.5 • 1.7
Step-by-step explanation:
I knew this answer. It is in distributive property.
Answer:
P = (13h+k+6m) cm
Step-by-step explanation:
Given that,
The side lengths of a triangle are :
(4h + 2k) cm, (9h + 4m) cm, and (2m - k) cm
We need to find the perimeter of the triangle.
We know that,
Perimeter = sum of all sides
So,
P = (4h + 2k)+(9h + 4m)+(2m - k)
= (4h+9h)+(2k-k)+(4m+2m)
= 13h+k+6m
Hence, the perimeter of the triangle is (13h+k+6m) cm.