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lord [1]
3 years ago
6

A powerful computer is purchased for $2000, but loses 20% of its value each year.

Mathematics
2 answers:
Alik [6]3 years ago
5 0

Answer:

It loses $400 a year

Step-by-step explanation

$2000 x 20% or .20 = $400 per year is what the computer loses.

It loses a great deal of value a year.

yKpoI14uk [10]3 years ago
3 0

Answer: 100n

Step-by-step explanation:

Each year it looses 100$ of its value each year.

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Which equation, when graphed would appear narrower than the graph of y= 3x2 + 5
maria [59]

Answer:

y = 4x^2 + 5 has the narrowest graph.

Step-by-step explanation:

The larger the coefficient of x^2 is, the narrower the graph will be.  Thus:

y = 4x^2 + 5 has the narrowest graph.

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The ratio of teachers to students is 1 to 7. if there are 5 teachers, how many students are there?
aleksandrvk [35]

there are 35 students..

5 0
3 years ago
Due in 8 hours, 21
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The answer to this question is 29.542 hectares
6 0
3 years ago
A standard die is rolled two times. What is the probability that it lands on 5 both times?
klio [65]

Answer:

1/36

Step-by-step explanation:

A die can roll a 1,2,3,4,5,6

P (5) = number of 5's / total

        = 1/6

The 2nd roll is independent so the probability is the same

P (5) = number of 5's / total

        = 1/6

P(5, 5) = 1/6*1/6 = 1/36

8 0
3 years ago
A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
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