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just olya [345]
3 years ago
5

Missing balanced formula equation F2+H2S....................+2HF?​

Chemistry
1 answer:
s344n2d4d5 [400]3 years ago
5 0

Answer:

Sulphur (S)

Explanation:

F2 + H2S ¬¬¬> S+2HF

As we have 2 F and 2 H, they combine to form 2HF. We are left with S only

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Question 6 The mineral barite, (BaSO.) has a ke of 1.1 x 10" at 25°C. Calculate the solubility of barium sulfate in water, in: 6
Sav [38]

Explanation:

(6.1).    The reaction equation will be as follows.

             BaSO_{4}(s) \rightleftharpoons Ba^{2+}(aq) + SO^{2-}_{4}(aq)

Assuming the value of K_{sp} as 1.1 \times 10^{-10} and let the solubility of each specie involved in this reaction is "s". The expression for K_{sp} will be as follows.

            K_{sp} = [Ba^{2+}][SO^{-}_{2}]    (Solids are nor considered)

                        = s \times s

                   s = \sqrt{K_{sp}}

                      = \sqrt{1.1 \times 10^{-10}}

                      = 1.05 \times 10^{-5}

Therefore, solubility of barium sulfate in water is 1.05 \times 10^{-5}.

(6.2).   As the molar mass of BaSO_{4} is 233.38 g/mol

Therefore, the solubility is g/L will be calculated as follows.

                233.38 g/mol \times 1.05 \times 10^{-5}

                  = 2.45 \times 10^{-3} g/L

Therefore, solubility of barium sulfate in grams per liter is 2.45 \times 10^{-3} g/L.

8 0
3 years ago
The density of no2 in a 4.50 l tank at 760.0 torr and 25.0 °c is ________ g/l.
kap26 [50]
From  ideal  gas  equation   that   is   PV=nRT
n(number of  moles)=PV/RT
P=760 torr
V=4.50L
R(gas  constant =62.363667torr/l/mol
T=273 +273=298k
n  is   therefore   (760torr x4.50L) /62.36367 torr/L/mol  x298k  =0.184moles
the  molar  mass  of  NO2 is  46  therefore  density=  0.184  x  46=8.464g/l
7 0
3 years ago
Read 2 more answers
HeLppP asap I’ll mark you as brainlister
andrezito [222]

Answer:

It's A

Explanation:

It starts as one molecule and splits into two which is the definition of a decomposition reaction

7 0
3 years ago
A 1dm3 solution was made by mixing 0.0040 mol of HCl(aq) and 0.0025 mol of NaOH(aq). What was the pH of the resulting solution?
kicyunya [14]

The pH of the resulting solution is 2.82.

<h3>What is pH ?</h3>

pH is the measure of acidity and alkalinity of a solution , It has a range of 1 to 14.

HCl          +                   NaOH      →         NaCl       +         H₂O

0.0040                         .0025                 0                       0

0.0040 -0.0025             0                   0.0025          0.0025

Moles of HCl = 0.0015

As 0.0025 moles of NaOH reacts with 0.0025 moles of HCl leaving behind 0.0015 moles of HCl

Concentration of HCl = 0.0015/ 1 = 0.0015 M

[ H⁺] = 0.0015 M

pH = -log [ H⁺]

pH = -log [ 0.0015]

pH = 2.82

Therefore the pH of the resulting solution is 2.82.

To know more about pH

brainly.com/question/15289741

#SPJ1

7 0
2 years ago
B. How many atoms are in 2.15 moles of water?
finlep [7]

Answer:

1.29*10^{24} mol

Explanation:

For this problem, you will have to convert moles to atoms.  Use Avogadro's number.

2.15 mol=\frac{6.022*10^{23} atoms}{1 mol}

7 0
4 years ago
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